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3 years ago

5

Please help me fast! I will give brainliest, if you show your work, and it is the right answer.

1 answer:

KATRIN_1 [288]3 years ago

5 0

You are given trapezoid WXYZ with two parallel sides WZ || XY.

Consider all options:

1. Line WZ has the same slope as line XY. This option is true, because parallel lines have the same slope.

2. Line YX has a greater slope than line ZY. Note that line XY has negative slope and line ZY has positive slope. Then the slope of line ZY is greater than the slope of line YX. This option is false.

3. Line XW has a lesser slope than line YZ. Both lines XW and YZ have positive slopes and line YZ is going up faster than line XW. This means that its slope is greater. Thus, this option is correct.

4. Line ZW has the same y-intercept as line WZ. Note that lines ZW and WZ are exactly the same line, therefore, the y-intercept is the same. This option is true.

5. Line XY has a greater y-intercept than line XW. Line XY has y-intercept at y=3 and line WX has its y-intercept somewhere about y=2. Then this option is true.

Answer: correct options are 1, 3, 4 and 5.

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Help me work this out I’m having trouble

Alborosie

The variable 'T' equals -20.

6 0

3 years ago

Select all of the expressions that are less than 10 2/3.

Dmitry_Shevchenko [17]

A. 10 2/3 x 9/10 = 9 3/5
D. 10 2/3 x 1/8 = 1 1/3
E. 10 2/3 x 3/5 = 6 2/5

Hope This Helps.

5 0

3 years ago

Enter the correct answer in the box. solve the equation x2 − 16x 54 = 0 by completing the square. fill in the values of a and b

poizon [28]

The roots of the given polynomials exist $x=8+\sqrt{10}$ , and $x=8-\sqrt{10}$ .

<h3>What is the formula of the quadratic equation?</h3>

For a quadratic equation of the form $a x^{2}+b x+c=0$ the solutions are

$x_{1,2}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Therefore by using the formula we have

$x^{2}-16 x+54=0$$

Let, a = 1, b = -16 and c = 54

Substitute the values in the above equation, and we get

$x_{1,2}=\frac{-(-16) \pm \sqrt{(-16)^{2}-4 \cdot 1 \cdot 54}}{2 \cdot 1}$$

simplifying the equation, we get

$$&x_{1,2}=\frac{-(-16) \pm 2 \sqrt{10}}{2 \cdot 1} \\$

$$&x_{1}=\frac{-(-16)+2 \sqrt{10}}{2 \cdot 1}, x_{2}=\frac{-(-16)-2 \sqrt{10}}{2 \cdot 1} \\$

$$&x=8+\sqrt{10}, x=8-\sqrt{10}$

Therefore, the roots of the given polynomials are $x=8+\sqrt{10}$ , and

$x=8-\sqrt{10}$ .

To learn more about quadratic equations refer to:

brainly.com/question/1214333

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3 0

1 year ago

Read 2 more answers

!! How could it be s

Nataly_w [17]

The solution to the system of equations are (2, 5).

Solution:

The system of equations are

x + y = 7 – – – – (1)

2x – y = –1 – – – – (2)

To find x from equation (1):

x + y = 7

Subtract y from both sides of the equation, we get

⇒ x + y – y = 7 – y

⇒ x = 7 – y – – – (3)

Substitute (3) in (2) we get,

2(7 – y) – y = –1

14 – 2y – y = –1

14 – 3y = –1

Subtract 14 from both sides,

–3y = –15

Divide by –5 on both sides,

y = 5

Substitute y = 5 in equation (3)

x = 7 – 5

x = 2

The solution to the system of equations are (2, 5).

7 0

3 years ago

freda makes 25,000 per year as a medical assistant. after working 6 months she receives a 6% pay raise. what is her new yearly s

gladu [14]

$26,000 because 25,000 × 0.06 = 1,500.

1,500 + 25,000 + 26,000

3 0

3 years ago

Read 2 more answers