What is 228/298 simplified to its lowest term?

Find the pattern rule for 1 - 210 2 - 200 3 - 190 4 - 180 5 - 170

chubhunter [2.5K]

It’s deducting 10 each

7 0

2 years ago

If the table shown below represents a function, then which is the possible value for f?

cluponka [151]

Answer:

C 2

Step-by-step explanation:

This is a parabolic function

Notice how we go negative and then positive

y = ax^2 +bx+c

Let x = 0

-5 = a(0) + b(0) +c

c = -5

y = ax^2 + bx -5

Let x = 3

4 = a(3)^2 +b(3) -5

Let x=-3

4 = a(3)^2 -b(3) -5

Add the two equations

4 = a(3)^2 +b(3) -5

4 = a(3)^2 -b(3) -5

----------------------------

8 = 2a (3)^2 - 10

18 = 2 a(9)

18 = 18a

a =1

Solving for b

4 = 1(3)^2 -b(3) -5

4 = 9 -3b -5

4 = 4 -3b

0 = -3b

0 =b

The equation is

y = (x)^2 -5

Letting y = -1

-1 =x^2 -5

Adding 5 to each side

4 = x^2

Taking the square root of each side

±2 = x

x= ±2

Given the choices

5 0

2 years ago

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

3 years ago

F(x) = 11x - 8

meriva

Solution:

100x^2-58x-16

6 0

2 years ago

Saydi is buying a pair of jeans that regularly cost $60. They are on sale for 40% off. If the tax rate is 9%,what is the sale pr

Karo-lina-s [1.5K]

Answer:

$39.24

Step-by-step explanation:

Let's determine the sale price before tax:

0.40($60) = $24 is the discount, so

the sale price is $60 - $24, or $36.

Multiplying this result by 1.09 results in the total price, including tax. It is $39.24.

6 0

3 years ago

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