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PIT_PIT [208]
3 years ago
7

Why cant a linear equation have two solutions

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
Systems of linear equations can only have 0, 1, or an infinite number of solutions. The two lines can't intersect twice, so the correct answer is that the system has one solution. 
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Find length of side X<br> Angle opposite x= 105 degrees <br> Side b= 18cm<br> Side c= 15cm
agasfer [191]
26.2 hope I helped good luck
8 0
2 years ago
What is the MODE of the data - (12, 8, 6, 12, 16, 12) *<br><br> help plsssss
Nostrana [21]

Answer: Mode = 12

Explanation: The mode is the most frequent value, so it is the value that shows up the most. In this case, that would be the value "12" since it shows up three times (while the other values only show up once).

7 0
3 years ago
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Consider a parallelogram in which one side is 3 inches long, another side measures 4 inches, and the measurement of one angle is
goldenfox [79]

Answer:

Only one parallelogram can be drawn based on the given conditions.

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7 0
3 years ago
Need help on math You have a meal at a restaurant. The sale tax is 8% . You leave a tip for the waitress that is 20% of the pret
DerKrebs [107]

Answer: $18

Step-by-step explanation:

Let x= Pretax price of the meal.

Given: Sales tax = 8%

Tip percent = 20%

As per given ,

Amount spent = ( Pretax price) + (Sales tax )  of (Pretax price) + (Tip percent)of (Pretax price)

=  x+ 8% of x +  20% of x

= x +0.08+0.20x

= 1.28x

∵ Amount spent =  $23.04

So,

1.28x=23.04\\\\\Rightarrow\ x=\dfrac{23.04}{1.28}\\\\\Rightarrow\ x=18

Hence, the pretax price of the meal= $18.

4 0
3 years ago
The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

5 0
3 years ago
Read 2 more answers
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