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PIT_PIT [208]
3 years ago
7

Why cant a linear equation have two solutions

Mathematics
1 answer:
mars1129 [50]3 years ago
4 0
Systems of linear equations can only have 0, 1, or an infinite number of solutions. The two lines can't intersect twice, so the correct answer is that the system has one solution. 
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Given the sequence 1/2 ; 4 ; 1/4 ; 7 ; 1/8 ; 10;.. calculate the sum of 50 terms
miv72 [106K]

<u>Hint </u><u>:</u><u>-</u>

  • Break the given sequence into two parts .
  • Notice the terms at gap of one term beginning from the first term .They are like \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} . Next term is obtained by multiplying half to the previous term .
  • Notice the terms beginning from 2nd term , 4,7,10,13 . Next term is obtained by adding 3 to the previous term .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

We need to find out the sum of 50 terms of the given sequence . After splitting the given sequence ,

\implies S_1 = \dfrac{1}{2},\dfrac{1}{4},\dfrac{1}{8} .

We can see that this is in <u>Geometric</u><u> </u><u>Progression </u> where 1/2 is the common ratio . Calculating the sum of 25 terms , we have ,

\implies S_1 = a\dfrac{1-r^n}{1-r} \\\\\implies S_1 = \dfrac{1}{2}\left[ \dfrac{1-\bigg(\dfrac{1}{2}\bigg)^{25}}{1-\dfrac{1}{2}}\right]

Notice the term \dfrac{1}{2^{25}} will be too small , so we can neglect it and take its approximation as 0 .

\implies S_1\approx \cancel{ \dfrac{1}{2} } \left[ \dfrac{1-0}{\cancel{\dfrac{1}{2} }}\right]

\\\implies \boxed{ S_1 \approx 1 }

\rule{200}2

Now the second sequence is in Arithmetic Progression , with common difference = 3 .

\implies S_2=\dfrac{n}{2}[2a + (n-1)d]

Substitute ,

\implies S_2=\dfrac{25}{2}[2(4) + (25-1)3] =\boxed{ 908}

Hence sum = 908 + 1 = 909

7 0
3 years ago
Need help plsss<br> Question is below
tatuchka [14]

Answer:

Step-by-step ex

its 0.2

5 0
3 years ago
The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = y minus 4 equals StartFra
Stels [109]

Answer:

Third option: y= \frac{1}{4}x+2

Step-by-step explanation:

<h3><em> The correct form of the exercise is: "The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y -4 = \frac{1}{4}(x -8). What is the slope-intercept form of the equation for this line?"</em></h3><h3><em /></h3>

<em> </em>The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope and "b" is the y-intercept.

Given the equation of the line in Point-Slope form:

y -4 = \frac{1}{4}(x -8)

You need to solve for "y" in order to write the given equation of the line in Slope Intercept form.

Then, this is:

y -4 = \frac{1}{4}(x -8)\\\\y-4= \frac{1}{4}x-\frac{8}{4}\\\\y-4= \frac{1}{4}x-2\\\\y= \frac{1}{4}x-2+4\\\\y= \frac{1}{4}x+2

You can identify that the slope "m" is:

m=\frac{1}{4}

And the y-interecept "b" is:

b=2

7 0
3 years ago
Read 2 more answers
Determine the inverse of the conditional statement: If My Mom has to work, then I babysit my little sister
leonid [27]
If I babysit my little sister, my Mom has to work.

Hope this helps! :D


5 0
3 years ago
Read 2 more answers
What two estimates is the quotient 345\8 between
grandymaker [24]
345/8 is the another one yes
4 0
3 years ago
Read 2 more answers
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