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Stolb23 [73]
2 years ago
7

Evaluate the expression 2n - 6 if n = 16.

Mathematics
2 answers:
irinina [24]2 years ago
5 0

Answer:

26

Step-by-step explanation:

This is the answer because:

1) First, we have to substitue the value that stand for n into the equation:

2(16) - 6

2) Next, we have to follow the order of operations in order to find the answer:

1. 2 x 16 = 32

2. 32 - 6 = 26

Therefore, the answer is 26.

Hope this helps! :D

V125BC [204]2 years ago
3 0

Answer:

26

Step-by-step explanation:

2n-6

Given that:

n=16

To evaluate the expression, we must simply substitute the given value of n, which is 16, for n:

2(16)-6

Multiply:

32-6

Subtract:

26

-

To check your work, simply set the given expression equal to our solution, 26:

2n-6=26

Add 6 to both sides of the equation:

2n=32

Divide both sides of the equation by the coefficient of n, which is 2:

n=16

Since it matches the given value of n, our solution is correct!

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as x approaches infinity, y constantly goes down, as x approaches -infinity, y constantly goes down

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A chemist has a 30% and a 45% acid solution. What amount of each solution should be used to make 500ml of solution with 35% acid
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What is -13m+46>-45 i really need help on it
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Answer:

Inequality form: m<7

Interval notation: (-infinity sign, 7)

Step-by-step explanation:

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3 years ago
Which series of transformations will not map figure H onto itself
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Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
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