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Lorico [155]
3 years ago
5

What is the solution to x – 10 > – 12? (–∞, –18) (–18, ∞) (–∞, 18) (18, ∞)

Mathematics
2 answers:
Allisa [31]3 years ago
8 0

Answer:

(18, ∞)

Step-by-step explanation:

(18, ∞) is the only option that works. if we ignore the "greater than" sign, and just set the function equal to -12, we see that x-10=-12 would give us x=-2. If we plug in -3 for x, we get -13, which is less than -12. if we plug in -1 for x, we get -11, which is greater than -12. Therefore, with the function only having one critical point (zero), we know that every value greater than -2 is a solution. Technically, the full solution would be (-2, ∞). however, the only answer available meeting the criteria would be (18, ∞).

Diano4ka-milaya [45]3 years ago
6 0

Answer:

ITS <u>B</u><u> </u><u>I</u><u> </u><u>got</u><u> </u><u>it</u><u> </u><u>wrong</u><u> </u><u>and</u><u> </u><u>looked</u>

Step-by-step explanation:

B b b b b b b b b b b b

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3 years ago
How do you know when to use the less than symbol and when to use the less than or equal to symbol when writing an inequality for
xenn [34]

Answer:

This depends on the situation. For context, you use less than when your inequality CANNOT exceed more than.

You would use less than or equal to if your inequality can be equal to a number. Here's an example.

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5 0
3 years ago
Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s
Ierofanga [76]

Option B:

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$\beta=10\log\left(\frac{I}{I_0} \right)

where I_0=1\times10^{-12}\ \text {watts}/ \text m^2}

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

10^{12}

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$10^{12}=\left(\frac{I}{I_0} \right)

$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)

Now, do the cross multiplication,

I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}

I=1\times\ 10^{0} \ \text {watts}/ \text m^2}

I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}

Option B is the correct answer.

Hence I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}.

5 0
3 years ago
If a certain number of Grade IV students share 28 or 39 skill books in Mathematics,there are remainders of 4 and 3 books. What i
nadya68 [22]

Answer:

  • 12 students

Step-by-step explanation:

<u>Below numbers are divisible by the number of students:</u>

  • 28 - 4 = 24
  • 39 - 3 = 36

<u>Lets find GCF of 24 and 36:</u>

  • 24 = 2*2*2*3
  • 36 = 2*2*3*3
  • GCF(24,36) = 2*2*3 = 12

The largest possible number of students is 12

7 0
2 years ago
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