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3 years ago

Help me please (I have to write something to post this question)

Mathematics

1 answer:

Feliz [49]3 years ago

7 0

Answer:

Step-by-step explanation:

to get from -6 to a 0, you add 6. 0+20 is 20, so that is how you get it

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At time t ≥ 0, the velocity of a body moving along the s-axis is v = t² -5t +4. When is the body moving backwards

katovenus [111]

Answer:

Step-by-step explanation:

The velocity of a moving body is given by the equation:

$v=t^2-5t+4 ,\, t\geq0$

Is the velocity is positive (v>0), then our object will be moving forwards.

And if the velocity is negative (v<0), then our object will be moving backwards.

We want to find between which interval(s) is the object moving backwards. Hence, the second condition. Therefore:

$v$

By substitution:

$t^2-5t+4$

Solve. To do so, we can first solve for t and then test values. By factoring:

$(t-4)(t-1)=0$

Zero Product Property:

$t=1, \text{ and } t=4$

Now, by testing values for t<1, 1<t<4, and t>4, we see that:

$v(0)=4>0,\, v(2)=-20$

So, the (only) interval for which v is <0 is the second interval: 1<t<4.

Hence, our answer is A.

7 0

3 years ago

What two numbers add up to -13 and multiply to 36?

vodka [1.7K]

-4 and -9 is the correct answer

6 0

3 years ago

Read 2 more answers

The diameter of a round rug is 42 inches. What is the approximate area of the rug?

aksik [14]

Answer:

D, It would be 1,385 Square Inches

Step-by-step explanation:

3 0

3 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At 95%, the data lies between μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39 and 83

At 99.7%, the data lies between μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28 and 94

the probability equivalent to 94 is when P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0

3 years ago

1) Suppose f(x) = x2 and g(x) = |x|. Then the composites (fog)(x) = |x|2 = x2 and (gof)(x) = |x2| = x2 are both differentiable a

Rufina [12.5K]

Answer:

This contradict of the chain rule.

Step-by-step explanation:

The given functions are

$f(x)=x^2$

$g(x)=|x|$

It is given that,

$(f\circ g)(x)=|x|^2=x^2$

$(g\circ f)(x)=|x^2|=x^2$

According to chin rule,

$(f\circ g)(c)=f(g(c))=f'(g(c)g'(c)$

It means, $(f\circ g)(c)$ is differentiable if f(g(c)) and g(c) is differentiable at x=c.

Here g(x) is not differentiable at x=0 but both compositions are differentiable, which is a contradiction of the chain rule

3 0

3 years ago

Help me please (I have to write something to post this question) ​

Help me please (I have to write something to post this question)