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jeyben [28]
3 years ago
7

Identify square root of 2 as either rational or irrational, and approximate to the tenths place.

Mathematics
2 answers:
Artist 52 [7]3 years ago
4 0
Definitely irrational, and I'd say 1.4
LuckyWell [14K]3 years ago
3 0
1.4142135623730950488016887242097 
its irrational

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Which value or in the solution set of the inequality − 2/3 x + 13 ≥ − 1
Svetach [21]

Answer:

x\leq21

Step-by-step explanation:

(-2/3)x+13≥ -1

    (-2/3)x≥ -14 (I subtracted by 13 on both sides)

             x\leq-14*(-3/2) (I divided by -2/3 on both sides)

             x\leq21

5 0
3 years ago
Enter the correct answer in the box. Add the two functions. f(x) = 3x3 + 7x − 26 g(x) = x + 2 Write your answer in the standard
kotykmax [81]

f(x) + g(x) = 3x³ + 8x - 24

that is 3x³ + 7x - 26 + x + 2 = 3x³ + 8x - 24


4 0
3 years ago
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What is the difference (2x-3)-(1-1)?<br> O x+2<br> O x4<br> Help please!!
AVprozaik [17]

Answer:

I don't know if I understood the question correctly, but this is what I have...

Step-by-step explanation:

If the "x" is a variable:

(2x-3)-(1-1)=

2x-3

If th "x" is a multiplication sign:

(2x-3)-(1-1)=

-6-0=

-6

i hope this helps

7 0
3 years ago
If you bought a stock last year for a price of $147, and it has risen 17.9% since then, how much is the stock worth now, to the
zysi [14]

Answer:

This is an percentage question, meaning you have to calculate the percentage rise.

1) Do 147 * 17.9% (Which equals to 26.3 [1.d.p.])

2) 26.3 is the answer

Hope it helps! :D

5 0
3 years ago
BRAINLIEST!!Felicia had $80 when she went to a music store that charges $18 for each CD. She needs to have no less than $20 in h
xxMikexx [17]

Answer:

The possible number of CDs she could buy is 1, 2, and 3.

Step-by-step explanation:

First, you have to make an equation to solve to find the answer(s):

  • 80 - (18 · x) ≥ 20
  • 80 is how much money Felicia has; 18 is for the cost of each CD; x is for the number of CDs; ≥ is no less; and 20 is how much money Felicia needs to have left.

1.) 80 - (18 · 1) ≥ 20

80 - 18 · 1 ≥ 20

80 - 18 ≥ 20

62 ≥ 20

Since 62 ≥ 20 is always true, there are infinitely many solutions.

2.) 80 - (18 · 2) ≥ 20

80 - 18 · 2 ≥ 20

80 - 36 ≥ 20

44 ≥ 20

Since 44 ≥ 20 is always true, there are infinitely many solutions.

3.) 80 - (18 · 3) ≥ 20

80 - 18 · 3 ≥ 20

80 - 54 ≥ 20

26 ≥ 20

Since 26 ≥ 20 is always true, there are infinitely many solutions.

4.) 80 - (18 · 4) ≥ 20

80 - 18 · 4 ≥ 20

80 - 72 ≥ 20

8 ≥ 20

Since 8 ≥ 20 is false, there is no solution.

5.) 80 - (18 · 5) ≥ 20

80 - 18 · 5 ≥ 20

80 - 90 ≥ 20

- 10 ≥ 20

Since - 10 ≥ 20 is false, there is no solution.

4 0
3 years ago
Read 2 more answers
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