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lys-0071 [83]
3 years ago
7

The ratio 6:7 can also be written as 7/6 True or false

Mathematics
1 answer:
zloy xaker [14]3 years ago
5 0
I think the answer is false✨
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A conditional statement is logically equivalent to a biconditional statement. True False pls help i have a test and i was absent
andreyandreev [35.5K]

Answer:

false.

Step-by-step explanation:

A conditional statement is something like:

If P, then Q.

This means that if a given proposition P is true, then another proposition Q is also true.

An example of this is:

P = its raining

Q = there are clouds in the sky.

So the conditional statement is

If its raining, then there are clouds in the sky.

A biconditional statement is:

P if and only if Q.

This means that P is only true if Q is true, and Q is only true if P is true.

So, using the previous propositions we get:

Its raining if and only if there are clouds in the sky.

This statement is false, because is possible to have clouds in the sky and not rain.

(this statement implies that if there are clouds in the sky, there should be rain)

Then we could see that for the same propositions, the conditional statement is true and the biconditional statement is false.

Then these statements are not logically equivalent.

The statement is false.

3 0
3 years ago
Please help with the questions in the image
allochka39001 [22]

Answer:

fghjk

Step-by-step explanation:

6 0
3 years ago
What number must each side of the equation
zysi [14]
<span>1. What number must multiply each side of the equation 2/5 x=10 to produce the equivalent equation x = 25? 4 5 5/2 1/5 2. Solve. -1/3 x=12 4 –36 –1/4 –4 3.Solve. 3|s| = 18 s = –6 or s = 6 s = 6 only s = –18 or s = 18 s = –6 only 4.Solve. x + 4 – 7x =...</span> show more Best Answer:<span>  </span><span>C 
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7 0
3 years ago
I need help with this question?????
ankoles [38]
She harvests roughly 11 and a half acres an hour
7 0
3 years ago
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What is the linear function equation represented by the graph?
igor_vitrenko [27]

Look at the picture.

The point-slope form of a line:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (0, 1) and (2, 0). Substitute:

m=\dfrac{0-1}{2-0}=\dfrac{-1}{2}=-\dfrac{1}{2}\\\\y-1=-\dfrac{1}{2}(x-0)\\\\y-1=-\dfrac{1}{2}x\qquad|+1\\\\y=-\dfrac{1}{2}x+1

Answer: f(x)=-\dfrac{1}{2}x+1

5 0
3 years ago
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