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3 years ago

Find the horizontal for oblique asymptote of f(x)=-3x^2+7x+1/x-2

1 answer:

eduard3 years ago

3 0

For greater clarity, please enclose the divisor (x-2) inside parentheses. Thx.

Divide x-2 into 3x^2 + 7x + 1:

3x + 13
__________________
x-2 / 3x^2 + 7x + 1
3x^2 - 6x
----------------
13x + 1
13x - 26
----------------
-27 (remainder)
-27
The quotient here is 3x + 13 - ------
x-2

The slant asymptote is the line y = 3x + 13. Note that -27 / (x-2) goes to zero as x grows large in either direction (positive or neg).

Note that you are looking for the "oblique" or "slant" asymptote here; there is no "horizontal" involved.

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3 years ago

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QUESTION :-

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3 years ago

Find the 97th term of the arithmetic sequence

kozerog [31]

<h2>Answer:</h2><h2>The 97th term in the series is 409</h2>

Step-by-step explanation:

The given sequence is 25, 29, 33, ....

The sequence represents arithmetic progression

In an AP, the first term is a1 = 25

The difference between two terms, d = 29 - 25 = 4

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By formula, $a_{n} = a_{1} + (n - 1) d$

Substituting the values in the above equation, we get

$a_{97} = 25 + (97 - 1) 4$

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3 years ago