Answer: 
Step-by-step explanation:
<h3>
The complete exercise is: "Line segment YV of rectangle YVWX measures 24 units. What is the length of line segment YX?"</h3><h3>
The missing figure is attached.</h3>
Since the figure is a rectangle, you know that:
Notice that the segment YV divides the rectangle into two equal Right triangles.
Knowing the above, you can use the following Trigonometric Identity:
You can identify that:
Therefore, in order to find the length of the segment YX, you must substitute values into and then you must solve for YX.
You get that this is:
Answer:
9600 sq in
Step-by-step explanation:
30 x 20 x 16 = 9600
This does not appear to be a right triangle. However, we know 2 sides and the included angle, so can find the unknown side length. Let x represent this length. Then:
x^2 = (9 m)^2 + (12 m)^2 - 2(9m)(12 m)*cos 30 degrees, or
x^2 = 81 + 144 - 216(sqrt(3) / 2). Please solve for x^2 and then solve the result for x, making sure to choose the positive value. The result will be the length of the side opposite the 30 degree angle.
With 1 of 3 angles known, and 3 of 3 sides known, you can use the Law of Sines to find the other two angles. As a reminder, the Law of Sines looks like this:
a b c
-------- = --------- = ----------
sin A sin B sin C.
You can give the 30-deg angle any name you want; then a, the length of the side opposite the 30-deg angle, which you have just found. And so on.
Answer:
Step-by-step explanation:
We want to find an equation of a line that's perpendicular to x=1 that also passes through the point (8,-9).
Note that x=1 is a <em>vertical line </em>since x is 1 no matter what y is.
This means that if our new line is perpendicular to the old, then it must be a <em>horizontal line</em>.
So, since we have a horizontal line, then our equation must be our y-value of our point.
Our y-coordinate of our point (8,-9) is -9.
Therefore, our equation is:
And this is in standard form.
And we're done!
Answer:
which one
Step-by-step explanation:
now gimme brainliest
