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3 years ago

Solve the system of equations using multiplication.

Mathematics

1 answer:

salantis [7]3 years ago

6 0

Answer:

B. (-3, -2)

Step-by-step explanation:

Multiply the first equation by -1/3 and add the result to the second equation.

-1/3(3x -3y) +(5x -y) = -1/3(-3) +-13

4x = -12 . . . . simplify

x = -3 . . . . . . divide by 4

Substituting this into -1/3 times the first equation, we get ...

-(-3) +y = 1

y = -2 . . . . . . . subtract 3

The solution is (x, y) = (-3, -2).

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(Help ASAP)(Will Mark Brainliest+5 Star rating+Thanks)

navik [9.2K]

<span> (17.) f(x)=x+3; g(x)=1/x^2

</span><span>If you take B f(x)=x+3 g(x)=1/x^2 plug the f(x) into the g(x) formula (in other words, f(x) becomes the x for g) g(x)=1/x^2 g(x)=1/(x+3)^2

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7 0

3 years ago

Each cement block weighs 4 3/5 pounds. How much do 3 cement blocks weigh in total?

natali 33 [55]

Answer:

13 4/5 pounds

Step-by-step explanation:

You multiply 4 3/5 by 3, which equals 13.8, which equals 13 4/5 pounds.

3 0

2 years ago

There is an ice cream and candy shop next door that is the same size as your bakery. How many thirtieths of the space does it ta

SSSSS [86.1K]

Answer:

135,000 times

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.

<u>We need to know the size of your bakery store. </u>

As we can see, the entire shopping center is: 45000 square feet and your shop is 1/10 of that space

=> Your shop area is: 45000*1/10 = 4500 square feet

In the question, they want to know how many thirtieths of the space does it take up, so let say thirtieths in numerical is: 1/30

Hence, the number of thirtieths it takes:

$\frac{Area}{Thirtieths}$ = $\frac{4500}{\frac{1}{30} }$ = 135,000 times

Hope it will find you well.

8 0

3 years ago

Hi can anyone help me with this ..

aleksley [76]

Answer:

n = π/6, π/4, 3π/4, 5π/6

Step-by-step explanation:

sin(3n) − sin n = cos(2n)

Use double and triple angle formulas:

(3 sin n − 4 sin³ n) − sin n = 1 − 2 sin² n

2 sin n − 4 sin³ n = 1 − 2 sin² n

4 sin³ n − 2 sin² n − 2 sin n + 1 = 0

Factor by grouping:

2 sin² n (2 sin n − 1) − (2 sin n − 1) = 0

(2 sin² n − 1) (2 sin n − 1) = 0

Solve:

2 sin² n − 1 = 0

2 sin² n = 1

sin² n = 1/2

sin n = √2/2

n = π/4, 3π/4

2 sin n − 1 = 0

2 sin n = 1

sin n = 1/2

n = π/6, 5π/6

4 0

3 years ago

Twice the difference of a number and 2 is at most -27

igor_vitrenko [27]

<h2>Explanation:</h2><h2 />

When we say "a is at most b" we mean that "a is less than or equal to b" or "a is not greater than b". So let's solve this problem as follows:

Step 1. Twice the difference of a number and 2

Let's call that unknown number as n. Then, twice the difference of a number and 2 is:

$2(n-2)$

Step 2. Twice the difference of a number and 2 is at most -27

$2(n-2)\leq -27$

_________________________________________

So the mathematical form of the statement <em>twice the difference of a number and 2 is at most -27 </em>is:

$\boxed{2(n-2)\leq -27}$

5 0

3 years ago