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eimsori [14]
3 years ago
10

N a 3 P O 4 (aq)+L i 2 S O 4 (aq)→ Express your answer as a chemical equation. Enter NOREACTION if no reaction occurs. Identify

all of the phases in your answer.
Chemistry
1 answer:
zavuch27 [327]3 years ago
3 0
NA3DO4+Li2PO4

Reaction type- double replacement
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A _______ is a segment of DNA that contains the information necessary to express the inherited traits of an organism. A. protein
Ilya [14]

Answer:

"gene" is the segment of DNA containg the inheritance information.

6 0
3 years ago
Complete the balanced equation for the reaction that occurs when formic acid (hcooh) dissolves in water. please include the stat
nignag [31]
Your balanced equation for this reaction is:

HCOOH (aq) + H2O (aq) → HCOO- (aq) + H3O+ (aq)

So from the reaction, we can see when formic acid dissolved in water so H3O+ ions will be formed.
and we can see that it is a balanced equation as:
we have H atoms = 4 on both sides of the reaction
and C atoms = 1 atom on both sides of the reaction
and O atoms = 3 atoms on both sides of the reaction
So it is our final balanced equation of the reaction.
8 0
3 years ago
Determine the mass of 10g of CaCO3​
NISA [10]

Answer:

= 100u. Hence 10 g = 0.1 mole. Hope it's helpful to u

3 0
2 years ago
A single serving bag of snack chips contains 65.0 Cal. Assuming that all of the energy from eating these chips goes toward keepi
AveGali [126]

Answer:

= 62.1 hours

Explanation:

Energy provide by the serving is 65 cal

= 65 cal  × 4.184 Kj = 271.96 kJ

271.96 KJ = 271960 J

Energy required for 1minute of energy

= 73 x 1

= 73 J/min

So, 271960 joules will be required for 271960 heart beat

Minutes = 271960 / 73

= 3593.94 minutes  

Time in hours = 3725.429 / 60

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5 0
4 years ago
Calculate the mass of water produced when 42 g of propane, c3h8, is burned with 115 g of oxygen
gavmur [86]
The balanced combustion reaction of propane, C₃H₈, is

C₃H₈ + 5 O₂ → 3 CO₂ + 4 H₂O

Molar mass of propane: 44 g/mol
Moles of propane = 42 g * (1 mol/44g) = 0.9545 mol propane

Molar mass of oxygen: 32 g/mol
Moles of oxygen = 115 g * (1 mol/32 g) = 3.594 mol oxygen

Moles of oxygen needed to completely react propane:
0.9545 mol propane * (5 mol O₂/1 mol propane) = 4.7725 mol oxygen

Since the available oxygen is only 3.594 moles and propane needs 4.7725 moles, that means oxygen is our limiting reactant. We base the amount of water produced here.

Molar mass of water: 18 g/mol
Mass of water produced = 3.594 mol O₂ * (4 mol H₂O/5 mol O₂) * (18 g/mol)
Mass of water produced = 258.768 grams
6 0
3 years ago
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