Question

For the formation of hydrogen iodide, H2(g) + 12(g) - 2HI(g) the value of the

Answer 1

Answer:

t 700 K, the equilibrium constant for the reaction;

H  

2(g)

​  

+I  

2(g)

​  

⇌2HI  

(g)

​  

 is 54.8.

If 0.5 mol litre  

−1

 of HI  

(g)

​  

 is present at equilibrium at 700 K, what are the concentrations of H  

2(g)

​  

 and I  

2(g)

​  

 assuming that we initially started with HI  

(g)

​  

 and allowed it to reach equilibrium at 700 K.