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JulijaS [17]
2 years ago
7

Write balanced chemical equations, including states, for the following reactions:

Chemistry
1 answer:
Kazeer [188]2 years ago
4 0

Answer:

MgCO 3 (s)+2HCl(aq)→MgCl 2 (aq)+CO2 (g)+H2 O(l)

Explanation:

MgCO 3 (s)+2HCl(aq)→MgCl 2 (aq)+CO2 (g)+H2 O(l)

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Why do we use ammonium formate as a hydrogen surrogate instead of using hydrogen gas in this experiment?
NemiM [27]

Answer:

Ammonium formate can also be used in palladium on carbon (Pd/C) reduction of functional groups. In the presence of Pd/C, ammonium formate decomposes to hydrogen, carbon dioxide, and ammonia.

Explanation:

This hydrogen gas is adsorbed onto the surface of the palladium metal, where it can react with various functional groups.

7 0
3 years ago
What is 2(NH,4)Cr,2 O,7
Vitek1552 [10]

oxidation-reduction.


4 0
3 years ago
Assuming complete distribution, what is the molarity of 10 milligrams of lisinopril in 100 liters?
SVEN [57.7K]

Answer:

2.47x10^{-7}   M

Explanation:

Lisoprisil's molecular mass is 405.488g/mol, we'll use this fact to calculate molarity, which units are mol/L, and we proceed to the calculus:

  • First, we'll unify unities, the 10 milligrams of lisinopril we'll transform into grams.

10mg*\frac{1g}{1000mg}=0.01g

  • Now that we have the same unities we'll calculate molarity using the molecular mass, the grams of lisinopril and the liters in which these grams are, let's consider that our final unities have to be mol/L.

\frac{1mol}{405.488g}*\frac{0.01g}{100L}=2.47x10^{-7}   M

I hope you find this information useful and interesting! Good luck!

3 0
3 years ago
How many moles are in 1.23 X 1050 atoms of calcium carbonate, CaCO3?
pav-90 [236]

Answer:

Explanation:1 mole is equal to 1 moles CaCO3, or 100.0869 grams.

8 0
3 years ago
1. Unas de las formas de producir nitrógeno gaseoso (N2) es mediante la oxidación de metilamina (CH3NH2), tal como se muestra en
Maslowich

Answer:

a) 4CH₃NH₂ + 9O₂ ⇄  4CO₂ + 10H₂O + 2N₂    

b) m = 5,043 g

c) % = 69,4 %

Explanation:

a) La ecuación balanceada es la siguiente:

4CH₃NH₂ + 9O₂ ⇄  4CO₂ + 10H₂O + 2N₂              

En el balanceo, se tiene en la relación estequiométrica que 4 moles de metilamina reacciona con 9 moles de oxígeno para producir 4 moles de dióxido de carbono, 10 moles de agua y 2 moles de nitrógeno.  

b) Para determinar la masa de nitrógeno se debe calcular primero el reactivo limitante:

n_{O_{2}} = \frac{m}{M} = \frac{25,6 g}{31,99 g/mol} = 0,800 moles      

n_{CH_{3}NH_{2}} = \frac{4}{9}*0,800 moles = 0,356 moles

De la ecuación anterior se tiene que la cantidad de moles de metilamina necesaria para reaccionar con 0,800 moles de oxígeno es 0,356 moles, y la cantidad de moles iniciales de metilamina es 0,5 moles, por lo tanto el reactivo limitante es el oxígeno.

Ahora, podemos calcular la masa de nitrógeno producida:

n_{N_{2}} = \frac{2}{9}*n_{O_{2}} = \frac{2}{9}*0,8 moles = 0,18 moles

m_{N_{2}} = n_{N_{2}}*M = 0,18 moles*28,014 g/mol = 5,043 g

Por lo tanto, se pueden producir 5,043 g de nitrógeno.

c) El redimiento de la reacción se puede calcular usando la siguiente fórmula:

\% = \frac{R_{r}}{R_{T}}*100

<u>Donde</u>:

R_{r}: es el rendimiento real

R_{T}: es el rendimiento teórico

\% = \frac{3,5}{5,043}*100 = 69,4

Entonces, el procentaje de rendimiento de la reacción es 69,4%.

Espero que te sea de utilidad!        

5 0
3 years ago
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