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2 years ago

Write balanced chemical equations, including states, for the following reactions:

Chemistry

1 answer:

Kazeer [188]2 years ago

4 0

Answer:

MgCO 3 (s)+2HCl(aq)→MgCl 2 (aq)+CO2 (g)+H2 O(l)

Explanation:

MgCO 3 (s)+2HCl(aq)→MgCl 2 (aq)+CO2 (g)+H2 O(l)

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1. The two qualities used to describe winds are________ and speed. 2. a local wing that blows during the day from an ocean towar

Mazyrski [523]

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3 years ago

It took batman 5 minutes to catch robin in the bat-mobile. If he traveled 45 km before catching him, how fast was he going?

Nataly_w [17]

Answer:

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Explanation:

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3 years ago

How many grams of NaCl (molecular weight = 58.4 g mole-1) would you dissolve in water to make a total volume of 500 mL of soluti

kolezko [41]

Given :

Volume , V = 500 mL .

Molarity , M = 0.5 M .

Molecular mass of NaCl is $58.4\ g/mole$ .

To Find :

How many grams of NaCl is required .

Solution :

Let , NaCl required is x gram .

Molarity is given by :

$M=\dfrac{\text{Number of moles}}{\text{Volume (in liters) }}\\\\M=\dfrac{m}{M\times V}\\\\0.5=\dfrac{x}{58.4\times 0.5}\\\\x=0.5^2\times 58.4\ g\\\\x=14.6\ g$

Hence , this is the required solution.

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3 years ago

Write the chemical equations for the neutralization reactions that occurred when hcl and naoh were added to the buffer solution.

irga5000 [103]

A base and an Acid always react to form a salt and water

So, HCl + NaOH —> NaCl + HOH

5 0

3 years ago

of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measu

krok68 [10]

The question is incomplete . The complete question is :

100 mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.107atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits.

Answer: The molar mass of the protein is $4.57\times 10^3g/mol$

Explanation:

$\pi =CRT$

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = 0.107 atm

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (protein) = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 5.00 mL

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$0.107=1\times \frac{0.1\times 1000}{\text{Molar mass of insulin}\times 5.00}\times 0.0821\text{ Latm }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of protein}$

$\text{molar mass of protein}=4.57\times 10^3g/mol$

Hence, the molar mass of the protein is $4.57\times 10^3g/mol$

7 0

3 years ago