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valentinak56 [21]
3 years ago
8

HELP ASAP 50 POINT FOR CORRECT ANSWER

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0
Im not sure but I think it is like 65

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2. Lamar purchases comic books at garage
Otrada [13]

<u>Answer:</u>

Lamar will charge\$7 to the comic dealer for a comic book.

<u>Solution:</u>

It is given that lamar purchases a comic book for \$4. He then marks up the price of a comic book by 75\% which means he increases the price of the book by 75\% and then sells it to the comic dealer.

We have to find out how much will he charge the comic book dealer.

New price of the book after lamar marks up the price is given by

New price =  \$4 + \frac{75}{100} \times \$4

=\$4 + \$3= \$7

Thus, lamar will charge \$7 to the comic dealer for a comic book.

4 0
3 years ago
How many groups of ten are there in 230?
Artyom0805 [142]

Answer:

I am pretty sure the answer is 23

Step-by-step explanation:

The answer is 23 because if you multiply 23 by 10 you get 230 which is the same if you divided 230 by 10 and you get 23.

4 0
3 years ago
Si un triángulo tiene una hipotenusa de 15 cm y un cateto que mide 12 cm, ¿cual es la longitud del otro cateto?
BartSMP [9]

Answer:

   

9cm

Explicación:

El teorema de pitagoras nos dice que la hipotenusa al cuadrado es igual a la suma de los catetos al cuadrado:

c^{2} =a^{2} + b^{2}

Donde c es la hipotenusa y a  y b son los catetos.

Por lo cual, podemos reemplazar c por 15cm y a por 12cm :

15^{2} =12^{2} +b^{2}

Finalmente , debemos resolver la ecuación para b, así que b es igual a :

225=144+b^{2} \\225-144=144+b^{2} -144\\81=b^{2} \\\sqrt{81} =b\\9=b

Por lo tanto, la longitud del otro cateto es 9 cm

3 0
2 years ago
4 (3x + 2)-6<br> I neeeed help
yuradex [85]

Answer:

12x - 2

Step-by-step explanation:

Step 1: Write expression

4(3x + 2) - 6

Step 2: Distribute 4

12x + 8 - 6

Step 3: Combine like terms

12x - 2

5 0
3 years ago
If D is an n × n diagonal matrix with entries dii, then det D = d11d22 ∙ ∙ ∙ dnn. Verify this theorem for 2 × 2 matrices.
nadya68 [22]

Answer:

Verified

Step-by-step explanation:

Let the diagonal matrix D with size 2x2 be in the form of

\left[\begin{array}{cc}a&0\\0&d\end{array}\right]

Then the determinant of matrix D would be

det(D) = a*d - 0*0 = ad

This is the product of the matrix's diagonal numbers

So the theorem is true for 2x2 matrices

8 0
2 years ago
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