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Andreyy89
3 years ago
8

Unit of Measurement, a punk/disco band, played a benefit concert for New Year's Eve. They started at 7:00 p.m. on New Year's Eve

and managed to play until 8:30 a.m. the following morning. How many minutes did they play in all?
Mathematics
1 answer:
Maksim231197 [3]3 years ago
6 0
810
count the number of hours they played which should be 13 hrs and 30 mins,
then since every hour is 60 mins multiply 60 by 13 and then add 30
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ra1l [238]
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The architect then solves this system of equations.
Nikolay [14]

Answer:

Step-by-step explanation:

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3 years ago
16: Find the coordinates of the foci and the vertices, the eccentricity, the length of the latus rectum of the Hyperbola y^2-16x
Morgarella [4.7K]

Answer:

Foci (0,\pm\frac{\sqrt{17}}{4})

Vertices:(0,\pm 1)

Eccentricity, e=\frac{\sqrt{17}}{4}

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Step-by-step explanation:

We are given that

y^2-16x^2=1

y^2-\frac{x^2}{(\frac{1}{4})^2}=1

The equation of hyperbola is along y-axis because y is positive

Compare the equation with

y^2/a^2-x^2/b^2=1 (Along y-axis)

We get

a=1, b=1/4

a^2+b^2=c^2

1+\frac{1}{16}=c^2

\frac{16+1}{16}=c^2

c^2=\frac{17}{16}

c=\pm \frac{\sqrt{17}}{4}

Therefore,

The coordinates of foci=(0,\pm c)=(0,\pm\frac{\sqrt{17}}{4})

The coordinated of vertices=(0,\pm a)=(0,\pm 1)

Eccentricity, e=c/a

e=\frac{\frac{\sqrt{17}}{4}}{1}=\frac{\sqrt{17}}{4}

Length of latus rectum=\frac{2b^2}{a}

Length of latus rectum=2\times \frac{1}{16}=\frac{1}{8}

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