What is the answer and equation to 2x+4(x+1/2+7

A computer can be classified as either cutting dash edge or ancient. Suppose that 86% of computers are classified as ancient.

Leno4ka [110]

Answer:

(a) The probability that both computers are ancient is 0.7396

(b) The probability that all seven computers are ancient is 0.3479

(c) The probability that at least one of seven randomly selected computers is cutting dash edge is 0.6520.

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

Step-by-step explanation:

We know that 86% of computers are classified as ancient. This means, if one computer is chosen at random, there is an 86% chance that it will be classified as ancient.

$P(ancient)=0.86$

(a) To find the probability that two computers are chosen at random and both are ancient you must,

The probability that the first computer is ancient is $P(ancient)=0.86$ and the probability that the second computer is ancient is $P(ancient)=0.86$

These events are independent; the selection of one computer does not affect the selection of another computer.

When calculating the probability that multiple independent events will all occur, the probabilities are multiplied, this is known as the rule of product.

Let A be the event "the first computer is ancient" and B the event "the second computer is ancient".

$P(A\:and \:B)=P(A)\cdot P(B)=0.86\cdot 0.86=0.86^2= 0.7396$

(b) To find the probability that seven computers are chosen at random and all are ancient you must,

Following the same logic in part (a) we have

Let A be the event "the first computer is ancient",

B the event "the second computer is ancient",

C the event "the third computer is ancient",

D the event "the fourth computer is ancient",

E the event "the fifth computer is ancient",

F the event "the sixth computer is ancient", and

G the event "the seventh computer is ancient"

$P(A\:and \:B\:and \:C\:and \:D\:and \:E\:and \:F\:and \:G)=\\P(A)\cdot P(B)\cdot P(C)\cdot P(D)\cdot P(E)\cdot P(F)\cdot P(G) =(0.86)^7=0.3479$

(c) To find the probability that at least one of seven randomly selected computers is cutting dash edge you must

Use the concept of complement. The complement of an event is the subset of outcomes in the sample space that are not in the event.

Let C the event "the computer is cutting dash edge".

Let A the event "the seven computers are ancient".

$P(C)=1-P(A)=1-0.3479=0.6520$

Because the probability is about 65% is it not unusual that at least one of seven randomly selected computers is cutting dash edge, it's more likely than not.

5 0

2 years ago

Can you please help me out?

larisa86 [58]

Answer:

- 3.5229

Step-by-step explanation:

Using the rules of logarithms

logx + logy = log(xy)

$log_{10}$ $10^{n}$ = n

Given

$log_{10}$ 3 ≈ 0.4771, then

$log_{10}$ 0.0003

= $log_{10}$ (3 × $10^{-4}$ )

= $log_{10}$ 3 + $log_{10}$ $10^{-4}$

≈ 0.4771 - 4

≈ - 3.5229 ( to 4 dec. places )

8 0

3 years ago

Julia bought stock at $281/8 per share. The value of each share increased by $65/8. How much is each share of stock now worth?

const2013 [10]

The worth of the share of stock is $ $34\frac{3}{4}$ .

<h3>What is the worth of the stock now?</h3>

A fraction is a non-integer that is made up of a numerator and a denominator. The numerator is the number above and the denominator is the number below.

A mixed fraction is a fraction that is made up of a whole number and a proper fraction. A proper fraction is a number where the numerator is less than the denominator.

The worth of the stock now = purchase price + increase in the share price

28 1/8 + 6 5/8

$34 \frac{1 + 5}{8}$