The complete similarity transformation is: triangle abc was dilated by a scale factor of [2], reflected across the [x-axis], and moved through the translation [0].
<h3><u>
What is Similarity?</u></h3>
- When it comes to Euclidean geometry, two things are said to be comparable if they have the same shape or the same shape as each other's mirror image.
- More specifically, by uniformly scaling (enlarging or decreasing), maybe with additional translation, rotation, and reflection, one can be created from the other.
- This indicates that one object may be properly aligned with the other object by rescaling, moving, and reflecting it. When two things are comparable to one another, one is consistent with the outcome of a specific uniform scaling of the other.
From the figure, we have:
AB = 2 units
DE = 4 units
So, the scale factor (k) is:
k = DE/AB
k = 4/2
k = 2
Also, both shapes are on either sides of the x-axis, and they are equidistant from the x-axis.
This means that the triangle is reflected across the x-axis with no translation.
Hence, the complete similarity transformation is: abc was dilated by a scale factor of [2], reflected across the [x-axis], and moved through the translation [0].
So, the scale factor is 2
Know more about Similarity with the help of the given link:
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I suspect this is what you mean, if let me know
2x(3)^2+x(2)^2
2(3)(9)+3(4)
54+12=66
Answer:
Step-by-step explanation:
x^2 + 48^2 = 50^2
x^2 + 2304 = 2500
x^2 = 196
x = 14
answer is a
Answer:
E) 29.0
Step-by-step explanation:
The value of the sum is obtained from 2 independent experiments: the value of the number of the first box X₁ and the value of the number of the second box X₂.
The expected value of a draw is the average of all its values, so E(X₁) = (1+2+3+4+5+6+7+8+9+10)/10 = 5.5 and E(X₂) = (20+21+22+23+24+25+26+27)/8 = 23.5
Hence, E(X₁+X₂) = E(X₁)+E(X₂) = 5.5+23.5=29
400/2 = 200
200 + 20 = 220
200 - 20 = 180
Answer: He had gone 220 miles.
He was 180 miles from the finish and 220 from the start, so he was 40 miles closer to the finish than to the start.