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Triss [41]
3 years ago
12

Suppose an auto racer won a 400 mile race with a time of ​1:41​:58. at one point the racer was 40 miles closer to the finish tha

n the start. how far had the racer gone at that​ point?
Mathematics
1 answer:
enot [183]3 years ago
7 0
400/2 = 200
200 + 20 = 220
200 - 20 = 180
Answer: He had gone 220 miles.

He was 180 miles from the finish and 220 from the start, so he was 40 miles closer to the finish than to the start.
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<span>Assuming the graph is y=-3(√2x)-4 and y=-3√(x-4) the transformation would be:

</span><span>The graph is compressed horizontally by a factor of 2
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TU = 3, RS = 15, TW = 4, TR = 9; Assume that the sides of triangle TUW are proportional to the sides of triangle TRS. What is th
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Answer:

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Step-by-step explanation:

we know that

If two triangles are similar

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we have

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\frac{TU}{TR}=\frac{TW}{TS}

substitute

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see the attached figure to better understand the problem

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