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Serhud [2]
3 years ago
8

What is the area of a right triangle with a base length of 4 inches and height of 4 inches?

Mathematics
2 answers:
Mice21 [21]3 years ago
4 0
The area of the triangle is 8 inches ^2
Afina-wow [57]3 years ago
4 0
The area of the triangle is 8 inches 
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If cot theta= 4/3, find csc theta
Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

csc^2\theta=cot^2\theta+1

Knowing that cot\theta=\frac{4}{3}:

Substitute it into csc^2\theta=cot^2\theta+1:

csc^2\theta=(\frac{4}{3})^2+1

Simplify the expression:

csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}

Solve for csc\theta. Apply square root at both sides of the expression:

\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}

csc\theta=\frac{5}{3}

8 0
3 years ago
I need help can you plz help me
horrorfan [7]

Simplify

10/3

Convert to a mixed fraction

3 1/3

4 0
3 years ago
What is the slope of the line represented by the equation y = -1/2x+1/4​
LUCKY_DIMON [66]

Answer: m=-1/2 which is the slope

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What’s is two plus the quotient of a number and five is the same as ten? As an equation?
Svet_ta [14]

The equation for this is 2 + n/5 = 10, where n is the number

7 0
3 years ago
Please please help me out
Dafna1 [17]

Answer:

The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,

4.2 ft

Step-by-step explanation:

The equation for the volume of a pyramid of base area B and height h is

V = (1/3)·B·h.  Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown.  First we find the height of this pyramid, and then the slant height.

V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.

Now to find the slant height of this pyramid:  That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).

Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.

The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,

4.2 ft

5 0
3 years ago
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