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Serhud [2]
3 years ago
8

What is the area of a right triangle with a base length of 4 inches and height of 4 inches?

Mathematics
2 answers:
Mice21 [21]3 years ago
4 0
The area of the triangle is 8 inches ^2
Afina-wow [57]3 years ago
4 0
The area of the triangle is 8 inches 
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Use the markings in the image to answer the following questions (drawing not to scale):
olga nikolaevna [1]

Hope this helps!

There are 3 images with full explanation

3 0
2 years ago
When does it reach maximum height?<br><br> H(t)=-16t^2+112t+288
ivolga24 [154]

Answer:

484 feet  maximum

Step-by-step explanation:

H(t)=-16t^2+112t+288

The maximum height occurs at the vertex of this graph.  

Let us find the vertex.

vertex x-coordinate = -b/2a

x =  -b/2a = -(112)/ (2*-16) =  7/2 sec.

H(7/2) = - 16 *(7/2)^2 + 112*(7/2) +  288

H(7/2) = -196 + 392 + 288 = 484 feet ..

5 0
3 years ago
The height, h, in feet of a golf ball above the ground after being hit into the air is given by the equation, h = -16t 2 + 64t,
coldgirl [10]

Answer:

4 seconds

Step-by-step explanation:

When the ball is on the ground h = 0, hence

- 16t² + 64t = 0 ( solve for t )

factor out - 16t

- 16t(t - 4) = 0

equate each factor to zero and solve for t

- 16t = 0 ⇒ t = 0

t - 4 = 0 ⇒ t = 4

the 0 solution is the height of the ball before being hit and

the time the ball takes to hit the ground is 4 seconds


6 0
3 years ago
302.406 + 7,710.826 What is the sum? ​
Alexus [3.1K]

Hi! I believe your answer is <u>8,013.232</u>. The work is shown below. I hope this helps you! Good luck and have a great day. ❤️✨

4 0
3 years ago
Read 2 more answers
CAN ANYBODY HELP ME OUT
bija089 [108]

Answer:

Correct option is

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

Step-by-step explanation:

Here, we are given the line RQ, which is divided in two equal parts by a line PS which is perpendicular to RQ.

The foot S of PS is on the line RQ.

First of all, let us do a construction here.

Join the point R with P and P with Q.

Please refer to the attached image.

Now, let us consider the triangles  PQS and PRS:

  • Side QS = RS (as given)
  • \angle PSR = \angle PSQ = 90^\circ
  • Side PS = PS (Common side in both the triangles)

Now, Two sides and the angle included between the two triangles are equal.

So by SAS congruence we can say that \triangle PRS \cong \triangle PQS

Therefore, the corresponding sides will also be equal.

RP = QP

RP is the distance between R and P.

QP is the distance between Q and P.

Hence, to prove that P is equidistant from R and Q, we have proved that:

b. If two sides and one included angle are equal in triangles PQS and PRS, then their corresponding sides are also equal.

7 0
3 years ago
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