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Anvisha [2.4K]
3 years ago
15

Which of the followings are true about D-glucose and L-glucose? A. They are furanose B. They are stereoisomers C. They are enant

iomers D. They are epimers E. They are non-reducing carbohydrates
Chemistry
1 answer:
zaharov [31]3 years ago
4 0

Answer:

B. They are stereoisomers

C. They are enantiomers

Explanation:

Let us consider all the options

A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)

B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.

C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions

D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case

E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid

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What is the acronym for ribonucleic acid?
Masteriza [31]
The acronym is RNA. Ribo Nucleic Acid
4 0
3 years ago
How many grams of sodium phosphate are formed by the reaction of 10 g of sodium with phosphoric acid?
Norma-Jean [14]

Answer:

23.8g of sodium phosphate are formed

Explanation:

Based on the reaction of sodium, Na, with phosphoric acid, H₃PO₄:

3Na + H₃PO₄ → Na₃PO₄ + 3/2 H₂

<em>3 moles of sodium produce 1 mole of sodium phosphate</em>

<em />

To solve this question we must find the moles of sodium in 10g. Using the chemical reaction we can find the moles -And the mass- of sodium phosphate produced, as follows:

<em>Moles Na -Molar mass: 22.99g/mol-</em>

10g * (1mol / 22.99g) = 0.435 moles Na

<em>Moles Na₃PO₄:</em>

0.435 moles Na * (1mol Na₃PO₄ / 3mol Na) = 0.145 moles Na₃PO₄

<em>Mass Na₃PO₄ -Molar mass: 163.94g/mol-</em>

0.145 moles Na₃PO₄ * (163.94g/mol) =

<h3>23.8g of sodium phosphate are formed</h3>
8 0
2 years ago
.
jolli1 [7]

Answer:

B. first level consumers.

Explanation:

The first level consumers are also the primary consumers. They are the animals that depends or rely on plants to transform chemical energy into carbohydrates and sugar.

Primary consumers are mostly herbivores. They feed on plant matter by which they derive their nutrition. They have special enzymes that helps to convert plant materials into substances needed for their body.

So, the first level consumer takes plant matter and convert them into useful food materials for their own nutrition.

The second level consumers depend on the first level consumers for nutrition.

3 0
2 years ago
PLEASE HELP!!!!! I'LL YOU BRAINIEST!!!!
Sidana [21]

Answer:

I believe 11 is B 12 is C 13 is B and 14 is C

3 0
2 years ago
The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea
Mariana [72]

Answer:

\frac{1}{8}  

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}  

We can construct a table.

<u>No of half-lives</u>  <u>Fraction remaining</u>

            1                       \frac{1}{2}  

            2                      \frac{1}{4}  

            3                      \frac{1}{8}  

The general formula is

\text{Fraction remaining} = \frac{1}{2^{n}}

where <em>n</em> = the number of half-lives.

Thus, \frac{1}{8} of the original carbon remains after 17 190 y.

8 0
3 years ago
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