The blank is filled by Na₂SO₄, and the complete equation for the double displacement reaction is:
Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl
<h3>What is a double displacement reaction?</h3>
It is a reaction in which both reactants exchange anions and cations.
Let's consider the following incomplete double displacement reaction.
_____ + BaCl₂ = BaSO₄ + 2 NaCl
If we compare the left and right sides, we can see that the missing ions in the left side are Na⁺ and SO₄²⁻. Thus, the missing compound is Na₂SO₄. The complete equation is:
Na₂SO₄ + BaCl₂ = BaSO₄ + 2 NaCl
Learn more about double displacement here: brainly.com/question/23918356
#SPJ1
The valence of helium is 0.
Answer:
A pre-bedtime snack can increase your metabolism, which causes the brain to become more active and can possibly lead to nightmares. If you notice that you have more bad dreams after having a late-night bite, make a goal not to snack after dinner, or at least to avoid heavy meals right before bed.
Answer:
3. A catalyst can convert an endothermic reaction into an exothermic reaction.
Explanation:
<em>What is NOT true for a catalyst? </em>
<em>1. A catalyst increases the rate of a chemical reaction by decreasing activation energy.</em> TRUE. A positive catalyst increases the reaction rate by decreasing the activation energy.
<em>2. A catalyst is not consumed in chemical reactions.</em> TRUE. A catalyst is recovered unaltered at the end of the reaction.
<em>3. A catalyst can convert an endothermic reaction into an exothermic reaction.</em> FALSE. A catalyst cannot modify the enthalpy of a reaction.
<em>4. A catalyst may be used in the solid, liquid or gaseous phase.</em> TRUE. If the catalyst is in the same phase as the reaction, the catalysis is homogeneous. Else, the catalysis is heterogeneous.
Answer:
87.5 % is the percent yield
Explanation:
We convert the mass of H₂ to moles: 4 g / 2g/mol = 2 moles of H₂
The reaction is: CO(g) + 2H₂(g) → CH₃OH(l)
So ratio is 2:1. Therefore, If I have 2 moles of hydrogen I would produce 1 mol of methanol.
So, as molar mass of methanol is 32g/mol; 32 g is the mass of produced methanol, at the 100 % yield reaction (theoretical yield)
Percent yield will be: (produced yield/ theoretical yield) . 100
(28 g / 32g) . 100 = 87.5 %