System of equations:
y = 6x + 104
y = 10x + 60
Method : <span>Substitution
Since the both equation is equal to y, you can substitute one equation for the other equation's y:
</span>
y = 6x + 104
10x + 60 = 6x + 104
-6x -60 =-6x -60
-------------------------------
4x = 44
---- -----
4 4
x = 11
Answer : It would take 11 days.
Answer:
<h2><u><em>My discord server is very close to 100 members</em></u></h2><h2><u><em>the code is: qSnYEsP</em></u></h2><h2><u><em>please join it :)</em></u></h2><h2><u><em>Or you can copy my name and paste it into the discord join server thing</em></u></h2><h2><u><em>both works</em></u></h2>
Step-by-step explanation:
Answer:
What is the arc length and sector area for the following circle. Round your answer to 4 decimal places.
Step-by-step explanation:
Answer: x≤0 is the answer or (−∞,0
]
Step-by-step explanation:
Answer:
x=3,5
Explanation:
x2−8x+15=0
Try to express the terms of the equation in square form.
Adding 16 both sides of the equation,
(x2−2⋅x⋅4+42)+15=16
or,(x−4)2+15−16=0
or,(x−4)2−1=0
or,(x−4)2−12=0
This is the a2−b2=(a+b)(a−b)form.
(x−4+1)(x−4−1)=0
or,(x−3)(x−5)=0
Now, equate both the terms to zero since both of them when multiplied, give zero.
Either,
x−3=0
∴x=3
Or,
x−5=0
∴x=5
Ans:x=3,5 Hope this helpsXD...!!
