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3 years ago

The 8th term of an arithmetic sequence is 12.5 and the 13th term is 20. What is the 25th term?

1 answer:

7 0

From the 8th to the 13th there are five numbers, and the difference between the 8th and the 13th is 20-12.5=7.5, so the difference between two neighboring number is 7.5÷5=1.5
from the 13th and the 25th there are 12 numbers, so the total difference is 12*1.5=18
so the 25th term is 20+18=38

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3 years ago

Read 2 more answers

Solve using elimination x-2y=12 and 5x+3y=-44 (4,8) (-4,8) (4,-8) (-4,-8)

Leya [2.2K]

Answer:

(-4, -8)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
Solving systems of equations using substitution/elimination

Step-by-step explanation:

Step 1: Define Systems

x - 2y = 12

5x + 3y = -44

Step 2: Rewrite Systems

x - 2y = 12

[Multiplication Property of Equality] Multiply everything by -5: -5x + 10y = -60

Step 3: Redefine Systems

-5x + 10y = -60

5x + 3y = -44

Step 4: Solve for y

Elimination

Combine 2 equations: 13y = -104
[Division Property of Equality] Divide 13 on both sides: y = -8

Step 5: Solve for x

Define original equation: x - 2y = 12
Substitute in y: x - 2(-8) = 12
Multiply: x + 16 = 12
[Subtraction Property of Equality] Subtract 16 on both sides: x = -4

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3 years ago