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3 years ago

8

Ricky and Sam each bought a remote control car for $80. A few months later they both sold it. Ricky sold his car for 25% less th

an the original price and Sam sold his car for 30% less than the original price. How much more did Ricky get than Sam?

1 answer:

murzikaleks [220]3 years ago

5 0

Answer:

Ricky get $4 than Sam.

Step-by-step explanation:

.25x80=20

80-20=60

.30×80=24

80-24=56

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Evaluate: -(-1) + (-7) + (2) - (-4) - (-2) A) -2 B) 0 C) 1 D) 2'

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Answer:

2

Step-by-step explanation:

-(-1) + (-7) + (2) - (-4) - (-2) =

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= -6 + 2 + 4 + 2

= -4 + 4 + 2

= 0 + 2

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2 years ago

The perimeter of a rectangular garden used 86 feet of barbed wire. The length of the garden is 7 feet more than its width. Find

Taya2010 [7]

Answer:

Step-by-step explanation:

perimeter of a rectangle = twice the length plus twice the width

P = 2L + 2W equation 1 P = 86 ft

Given the length is seven feet more than the width

L = W + 7 equation 2

Substitute equation 2 into equation 1

P = 2(W+7) + 2W = 86 ft

2W +14 + 2W = 86 ft

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2 years ago

Can someone help me solve parts (a) and (c) please? Thank you!

Brilliant_brown [7]

a) 4x +6

Add up all the sides to calculate perimeter

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2 years ago

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge

Ede4ka [16]

Answer:

Part a) The quadratic function is $4x^{2} +20x-39=0$

Part b) The value of x is $1.5\ in$

Part c) The photo and frame together are $7\ in$ wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

$(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0$

Part b) What is the value of x?

Solve the quadratic equation $4x^{2} +20x-39=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem

we have

$4x^{2} +20x-39=0$

so

$a=4\\b=20\\c=-39$

substitute in the formula

$x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}$

$x=\frac{-20(+/-)\sqrt{1,024}} {8}$

$x=\frac{-20(+/-)32} {8}$

$x=\frac{-20(+)32} {8}=1.5\ in$ -----> the solution

$x=\frac{-20(-)32} {8}=-6.5\ in$

Part c) How wide are the photo and frame together?

$(4+2x)=4+2(1.5)=7\ in$

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3 years ago

What multiplies to 30 but adds to -7

FinnZ [79.3K]

10 * 3

hope I helped :)

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2 years ago

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