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Lemur [1.5K]
2 years ago
15

A teacher puts five packages of craft paper into a cabinet each package has 80 sheets of paper what is the total number of sheet

s of craft paper that the teacher put into the cabinet and wears a.40 b.85 c.400 d.450

Mathematics
2 answers:
aliina [53]2 years ago
7 0

Answer:

C

Step-by-step explanation:

If we have 5 packages and each contains 80, we are basically doing 80+80+80+80+80 (5 TIMES) which is referred to as 80×5=400

jekas [21]2 years ago
6 0

Answer:

<u>1 package contain 80 sheets of paper.</u>

If there is 5 packages, there will be 'x' sheets of paper.

We replace the sheets of paper with 'x', because the value of x is unknown.

Now we set up the equation:

<h3>Sheets               80                 x</h3>

__________   _________ = _________, solve for x;

<h3> Packages           1                   5</h3>

80/1 = x/5

*5        *5

<u>400 = x</u>

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Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a red card
joja [24]

Answer: \dfrac{3}{51}

Step-by-step explanation:

Given : The total number of cards in a deck = 52

Number of red cards = 26

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The probability that the first card is a diamond :-

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Since diamond is also a red card.

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The probability that the second card is a red card (without repetition) is given by :-

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3 years ago
Speed can be found using the formula s = d/t (d = distance, t = time). True or false
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8 0
3 years ago
Read 2 more answers
PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%
Yanka [14]

Answer:

x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}

Second equation:

\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}

Third equation:

\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}

Now we use this value for "x" back in equation 1 to solve for "y":

1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}

And finally we solve for the third unknown "z":

\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12

8 0
3 years ago
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