when two waves superimposed then the resultant wave will have more energy and more intensity
It is because the resultant amplitude will be increased and given by the following equation
so here due to superposition since amplitude is increased so the energy or power of the wave will be increased
There is no effect on frequency , tension and density after superposition of waves and it will remain the same
SO energy is given as
here k = constant
A = amplitude
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Answer:
FC vector representation
Magnitude of FC
Vector direction FC
degrees: angle that forms FC with the horizontal
Explanation:
Conceptual analysis
Because the particle C is close to two other electrically charged particles, it will experience two electrical forces and the solution of the problem is of a vector nature.
The directions of the individual forces exerted by qA and qB on qC are shown in the attached figure; The force (FAC) of qA over qC is repulsive because they have equal signs and the force (FBC) of qB over qC is attractive because they have opposite signs.
The FAC force is up in the positive direction and the FBC force forms an α angle with respect to the x axis.
degrees
To calculate the magnitudes of the forces we apply Coulomb's law:
Equation (1): Magnitude of the electric force of the charge qA over the charge qC
Equation (2)
: Magnitude of the electric force of the charge qB over the charge qC
Known data
Problem development
In the equations (1) and (2) to calculate FAC Y FBC:
Components of the FBC force at x and y:
Components of the resulting force acting on qC:
FC vector representation
Magnitude of FC
Vector direction FC
degrees: angle that forms FC with the horizontal
Answer:
θ = 56.09°
Explanation:
Given that
h = 8.5 ft
speed ,u= 28 ft/s
We know that acceleration due to gravity g
g= 32.2 ft/s²
The maximum height h is given as
Now by putting the values
θ = 56.09°
Therefore the angle will be θ = 56.09°