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3 years ago

4. What is a good definition for Period?

Physics

1 answer:

lions [1.4K]3 years ago

3 0

Answer:

Explanation:

The time taken for a wave to complete one circle meaning time to reach the same successive crest or through of a wave.

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A mixture of nitrogen and water vapor at 200oF, 1 atm has the molar analysis of 80% N2, 20% water vapor.a) If the mixture is coo

Illusion [34]

Answer:

$p_g = 57.64 lb/in^2$

Explanation:

Given data:

temperature of water vapor is 200 degree F

pressure is 1 atm

\from the standard water temperature tables , at temperature 200 degree F

$p_{sat} = 11.538 psia$

$\omega_1 = \frac{0.622 \times 0.2 \times 11.538}{14.7 - (0.2\times 11.538)}$

$\omega_1 = 0.115$

at temp 200 degree F and $\omega _1 = 0.115$

$\phi = 0.255$

so relative humidity is given as

$\phi = \frac{p_v}{p_g}$

$0.255 = \frac{14.7}{p_g}$

$p_g = 57.64 lb/in^2$

6 0

4 years ago

Not sure what im doing wrong on this, I've been using the equation <img src="https://tex.z-dn.net/?f=y_%7Bf%7D%20%3Dy_%7Bi%7D%20

denpristay [2]

Answer:

for text

Explanation:

I think it's correct

6 0

3 years ago

suppose that the man pictured on the front side is orbiting the earth (mass=5.98 x 10^24kg at a distance of 310 miles above the

wlad13 [49]

Answer:

a = 9.81[m/s^2]; v = 18683.5[m/s]

Explanation:

The stament of the problem is:

Suppose that the man pictured on the front side is orbiting the earth (mass = 5.98 x 1024kg) at a distance of 310 miles (1600 meters = 1 mile) above the surface of the earth (radius = 4000 miles).

a. What acceleration does he experience due to the earth's pull?

b. What tangential velocity must he possess in order that he orbit safely (in m/s)?

First we need to convert all the initial data to units of the SI

Rs = 310 [mil] = 498897 [m]

RT= 400 [mil] = 643738 [m]

r = Rs + RT = 1142635 [m] "distance from the center of the earth to the man"

$F=G*\frac{M*m}{r^{2} } \\where:\\$

G = universal gravitational constant

M = mass of the earth [kg]

m = mass of the man [kg]

r = distance from the center of the earth to the man [m]

The acceleration he is experimenting is the same acceleration given by the gravity, therefore:

a = g = 9.81[m/s^2]

To find the tangential velocity, we must determinate the force exerted by the earth.

Now we will find the force exerted by the gravity when the man is orbiting the earth at distance r.

$G = 6.67*10^{-11} [\frac{N*m^{2} }{kg^{2} } ]\\M=5.98*10^{24}[kg]\\ m=100 [kg]\\Replacing:\\F = G*\frac{M*m}{r^{2} }$

$F = 6.67*10^{-11}*\frac{5.98*10^{24}*100 }{1142635^{2} } \\ F= 30550 [N]$

And this force will be equal to the following expression:

$F = m*\frac{v^{2} }{r} \\where:\\v= tangential velocity [m/s]\\v=\sqrt{\frac{F*r}{m} } \\v=\sqrt{\frac{30550*1142635}{100} } \\v=18683.5[m/s]$

8 0

3 years ago

What change takes place in a wave when the frequency of the wave increases?

Musya8 [376]

The answer is C. As the frequency of the waves increases, a greater number of wavelengths pass a given point per second. From the wave formula, we see that there is an indirect relationship between frequency and the wavelength. thus, as the frequency increases the wavelength decreases resulting to a smaller distance between the waves which will show greater number of wavelengths between waves.

4 0

3 years ago

How long is the flea in the air from the time it jumps to the time it hits the ground

Katen [24]

Answer:

0.613 milliseconds

Explanation:

7 0

3 years ago