All categories

2 years ago

How does sugar affect the attention of small children?

2 answers:

7 0

Sugar can have a powerful effect on children's behavior, and this is often in direct proportion to the amount of sugary foods they consume. ... When sugary foods are consumed regularly, it can affect attention span and learning ability, and can aggravate hyperactivity in children with ADHD.

soldi70 [24.7K]2 years ago

4 0

It hypes them up to a point they run wild

You might be interested in

A 946.4 kg ( 2083 lb ) car is moving at 14.8 m / s ( 33.0 mph ) . Calculate the magnitude of its momentum.

IgorLugansk [536]

Answer:

14009. 72 kgms^-1

Explanation:

Momentum is the product of an objects mass and velocity

7 0

3 years ago

LOTS OF BRAINLIST WILL BE GIVING TO THOSE WHO HELP

Alex_Xolod [135]

You know you can skip those and just submit them, they don’t even check them

4 0

2 years ago

Read 2 more answers

imagine that 501 people are present in a movie theater of volume 8.00 x10^3 that is sealed shut so no air can escape. Each perso

Semenov [28]

Answer:

The temperature of air will increase by $\Delta T=41044.967\ K$

Explanation:

Given:

no. of person in a theater, $n=501$

volume of air in the theater, $V=8\times 10^3\ m^3$

rate of heat given off by each person, $P=110\ J.s^{-1}$

duration of movie, $t=2\ hr=7200\ s$

initial pressure in the theater, $p_i=1.01\times 10^5\ Pa$

initial temperature in the theater, $T_i=20+273=293\ K$

specific heat capacity of air at the given conditions, $c=1.0061\ J.kg^{-1}.K^{-1}$

The total quantity of heat released by the total people in the theater during the movie:

$Q=n.P.t$

$Q=501\times 110\times 7200$

$Q=396792000\ J$

Form the relation of heat capacity:

$Q=m.c.\Delta T$

∵ $p_i.V=m.R.T$

$Q=(\frac{p_i.V}{R.T}) \times c\times (T_f-T_i)$

$396792000=(\frac{1.01\times 10^5\times 8\times 10^3}{287\times 293}) \times 1.0061\times (T_f-293)$

$T_f=41337.967\ K$

Change in temperature of air:

$\Delta T=41044.967\ K$

8 0

2 years ago

An airplane flies eastward and always accelerates at a constant rate. at one position along its path it has a velocity of 26.3 m

galina1969 [7]

We will use the formula / equation to determined the time.

Distance = ½ * (vi + vf) * t
48100 = ½ * (26.3 + 41.9) * t
t = 48100 ÷ 34.1 = 1410.557185 seconds

We will use the formula / equation to determined the acceleration.

vf = vi + a * t
41.9 = 26.3 + a * 1410.557185
a = (41.9 – 26.3) ÷ 1410.557185 = 0.011059459 m/s^2

We will use the formula / equation to determined the acceleration.

vf^2 = vi^2 + 2 * a * d
41.9^1 = 26.3^2 + 2 * a * 48100
a = (41.9^2 – 26.3^2) ÷ 96200 = 0. 011059459 m/s^2
Since both answers are the same, I believe the acceleration is correct.

6 0

3 years ago

If the kinetic energy of a 10 kilogram object is 2000 joules It’s velocity is

Vika [28.1K]

<h2>✨✨✨✨✨✨✨✨✨✨✨</h2><h2>hope it helps you see the attachment for further information.....</h2><h2 /><h2>✨✨✨✨✨✨✨✨✨✨✨</h2>

4 0

3 years ago