Question

At what angle should the player aim the ball if it is thrown from a height of 8.5 ftft with a speed of 28 ft/sft/s?

Answer 1

Answer:

θ = 56.09°

Explanation:

Given that

h = 8.5 ft

speed ,u= 28 ft/s

We know that acceleration due to gravity g

g= 32.2 ft/s²

The maximum height h is given as

$h=\dfrac{u^2sin^2\theta}{2g}$

Now by putting the values

$8.5=\dfrac{28^2sin^2\theta}{2\times 32.2}$

$sin^2\theta=0.69$

$sin\theta=0.83$

θ = 56.09°

Therefore the angle will be θ = 56.09°