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Svetllana [295]
3 years ago
5

A car insurance company has determined that 8% of all drivers were involved in a car accident last year. If 14 drivers are rando

mly selected, what is the probability of getting 3 or more who were involved in a car accident last year?
Mathematics
1 answer:
OLga [1]3 years ago
7 0

Answer:

0.0958

Step-by-step explanation:

Percentage involved in accident = 8% = 0.08

Number of drives selected = 14

Probability that 3 or more who were involved in a car accident last year?

P(x>=3) = P(x=3) or P(x>3)

Similarly;

P(x>=3) = 1-P(0<= x <=2)

P(x>=3) = 1-P(0<= x <=2)

Using the binomial probability calculator :

Cummulative probability :

P(X >= x) = 0.09583481948

= 0.0958

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Let

x--------> the number of blue beads

y--------> the number of red beads

we know that

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x=49-y -------> equation 1

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equate equation 1 and equation 2

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the answer is

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