4 years ago

Given: BC = 10 inches AC = inches m∠CBD = 60° m∠CAD = 90°

1 answer:

8 0

$\bf \textit{area of a segment of a circle}\\\\
A=\cfrac{r^2}{2}\left( \cfrac{\pi \theta}{180}\ - \ sin(\theta) \right)\qquad 
\begin{cases}
\theta=\textit{angle in degrees}\\
r=radius
\end{cases}$

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Question is not complete, so i have attached it.

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