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sweet [91]
3 years ago
12

Square root of 121/289

Mathematics
2 answers:
il63 [147K]3 years ago
5 0

Note that both 121 and 289 are perfect fractions:  121 = 11^2 and 289 = 17^2.

Thus,

121         11^2

------- = ---------- = (11/17)^2.

289        17^2  

The square root of this is merely 11/17.

nordsb [41]3 years ago
4 0

Answer:

\frac{11}{17}.

Step-by-step explanation:

Given  : \frac{121}{289}.

To find : square root.

Solution : We have given \sqrt{\frac{121}{289}}.

We can write the

121 as 11 *11 .

289 as 17 * 17.

By the radical rule : \sqrt{a*a} =a.

So, \sqrt{\frac{11*11}{17*17}} = \frac{11}{17}.

Therefore, \frac{11}{17}.

   

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The proportionality constant of the given graph is k = 16.

<h3>How to find the proportionality constant of a graph?</h3>

The proportionality constant of a graph is the ratio of the y-coordinates to the x-coordinates.

Thus, it is written as k = y1/x1 = x2/y2 = ... = yn/xn

<h3>Calculation:</h3>

The given graph has the coordinates as

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brainly.com/question/1835116

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