Answer:
initial magnitude will be 9 N and direction will be to the right
Explanation:
force= 9N
mass m= 330 grams
acceleartion = a
from newtons 2nd law of motion we write
dP is the chage in momentum dt is time taken and F is the Force applied
this shows that the rate of change of momentum is 9 N
we also know that F= ma
putting values we get
a= 27.27 m/sec^2
The direction of acceleration will along the direction of force applied. So will be the direction of change momentum as in F=ma, mass is the scalar quantity and direction of force dictates the direction of motion. Hence, initial magnitude will be 9N and direction will be to the right
Answer: 2.83 minutes
Explanation:
It is understood that trains are approaching. That is, they have speeds of equal magnitude but opposite. When train A travels x meters northbound, then train B travels the same distance southbound.
Therefore trains approach at a speed of:
Then:
Where x is the distance between the trains
So the time in which both trains meet is:
This is:
<em />
<em>How long will it be before they reach one another ?</em>
<h3>2.83 minutes</h3>
The magnitude of the induced emf is given by:
ℰ = |Δφ/Δt|
ℰ = emf, Δφ = change in magnetic flux, Δt = elapsed time
The magnetic field is perpendicular to the loop, so the magnetic flux φ is given by:
φ = BA
B = magnetic field strength, A = loop area
The area of the loop A is given by:
A = πr²
r = loop radius
Make a substitution:
φ = B2πr²
Since the strength of the magnetic field is changing while the radius of the loop isn't changing, the change in magnetic flux Δφ is given by:
Δφ = ΔB2πr²
ΔB = change in magnetic field strength
Make another substitution:
ℰ = |ΔB2πr²/Δt|
Given values:
ΔB = 0.20T - 0.40T = -0.20T, r = 0.50m, Δt = 2.5s
Plug in and solve for ℰ:
ℰ = |(-0.20)(2π)(0.50)²/2.5|
ℰ = 0.13V
15 because i did the math, had this assignment, and also watch a video
