Answer:
0.76
Explanation:
we are given:
radius (r) =5.7 m
speed (s) = 1 revolution in 5.5 seconds
acceleration due to gravity (g) = 9.8 m/s^{2}
coefficient of friction (Uk) = ?
we can get the minimum coefficient of friction from the equation below
centrifugal force = frictional force
m x r x ω^{2} = Uk x m x g
r x ω^{2} = Uk x g
Uk = 
where ω (angular velocity) = 
= 
= 1.14
Uk = 
= 0.76
1.8 mol of Na. hope this helps
The orbiting velocity of the satellite is 4.2km/s.
To find the answer, we need to know about the orbital velocity of a satellite.
<h3>What's the expression of orbital velocity of a satellite?</h3>
- Mathematically, orbital velocity= √(GM/r)
- r = radius of the orbital, M = mass of earth
<h3>What's the orbital velocity of a satellite orbiting earth with a radius 3.57 times the earth radius?</h3>
- M= 5.98×10²⁴ kg, r= 3.57× 6.37×10³ km = 22.7×10⁶m
- Orbital velocity= √(6.67×10^(-11)×5.98×10²⁴/22.7×10⁶)
=4.2km/s
Thus, we can conclude that the orbiting velocity of the satellite is 4.2km/s.
Learn more about the orbital velocity here:
brainly.com/question/22247460
#SPJ1
Answer:
the new resister is 11 ohms.
Explanation:
Set it up like this.
1/x + 1/1.1 = 1 Subtract 1/1.1 from both sides
1/x = 1 - 1/1.1
1 - 1/1.1 = 1/11
1/x = 1/11 Cross multiply
11 = x
If 1/11 bothers you, you could do it it another way.
1 - 1/1.1 = (1.1 - 1 ) / 1.1 = 0.1 / 1.1 Multiply top and bottom by 10
0.1*10/(1.1 * 10 ) = 1 / 11
