Answer:
V_{average} = 
, V_{average} = 2 V
Explanation:
he average or effective voltage of a wave is the value of the wave in a period
V_average = ∫ V dt
in this case the given volage is a square wave that can be described by the function
V (t) = 
to substitute in the equation let us separate the into two pairs
V_average = 
V_average = 
V_{average} =
we evaluate V₀ = 4 V
V_{average} = 4 / 2)
V_{average} = 2 V
The distance is 97720.5 m
From the question, we have
P = 0.06 W × 2 = 0.12 W
d = ?
Sound intensity, I = P/4πd²
I = 10⁻¹² W/m²
10⁻¹² = 0.12/4πd²
d = 97720.5 m
The distance is 97720.5 m
Sound intensity :
The power carried by sound waves per unit area in the direction perpendicular to that region is known as sound intensity or acoustic intensity. The watt per square meter (W/m2) is the SI unit of intensity, which also covers sound intensity. Sound intensity is a measure of how quickly energy moves across a given space. The unit area in the SI measurement system is 1 m2. So Watts per square meter are used to measure sound intensity. As there will be energy flow in certain directions but not in others, sound intensity also provides a measure of direction.
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Answer: When you touch wet canvas, surface tension will draw water to your finger. However, the drop left behind where you touched, like any irregular point on an overhead surface, will draw condensation from inside the tent if it is humid.
All we can say is that the object's volume is about 41 liters. That's the same as the volume of water displaced.
We can't say anything about the object's weight. There is no direct connection between the weight of the object and the weight of the water it displaces.
