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Brilliant_brown [7]
3 years ago
6

A cruise ship made a trip to Guam and back. The trip there took 12 hours and the trip

Physics
1 answer:
vekshin13 years ago
6 0
15 because i did the math, had this assignment, and also watch a video
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Which statement describes the formation of the Milky Way galaxy?
Oliga [24]

Answer:

A disk formed of a long trail of stars coiled into a spiral.

Explanation:

5 0
3 years ago
A 1200-kg car initially at rest undergoes constant acceleration for 9.4 s, reaching a speed of 11 m/s. It then collides with a s
Natalka [10]

To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,

KE_i = KE_f

KE_f = \frac{1}{2} mv^2

Here,

m = Mass

V = Velocity

Replacing,

KE_f = \frac{1}{2} (12000)(11)^2

KE_f = 72600J

Therefore the  final kinetic energy of the two car system is 72.6kJ

8 0
4 years ago
Three different objects, all with different masses, are initially at rest at the bottom of a set of steps. Each step is of unifo
fgiga [73]

The definition of gravitational potential energy would gravitate allows to find the answers for the energy of each object on the highest rung of the ladder are:

 a) expression for gravitational potential energy is  U_p = m g \ \Delta y

 b) Energy value

        * Body 1    U_p = 82 J

        * Body 2   U_p = 38.6 J

        * Body  3  18.5 J

The gravitational potential energy is a configuration energy that represents the amount of work that the system can do for a given configuration, its expression is

           U_p = m g \  \Delta y

Where U_p is the gravitational potential energy, m the mass of the body and Δy the difference in height.

In this case it indicates that the minimum height is at the bottom and is equal to zero, the steps of a ladder have a height of approximately y = 15 cm = 0.15 m

They indicate the mass of the bodies are m₁ = 3.10 kg, the mass of the body 2 m₂ = 1.46 kg , the mass of the third object is not observed, suppose it is m₃ = 0.7 kg.

They indicate that the body is placed on the last step, suppose it is a standard 18-step ladder, therefore the total height is

          y = # _ steps    y_each step

          y = 18   0.15

          y = 2.70 m

the gravitational potential energy to the capacity of the body is

body 1

              U_p = m₁ g Δy₁

              U_p = 3.10  9.8 (2.70 -0)

               U_p = 82 J

body 2

              U_p = 1.46 9.8 ( 2.7-0)

              U_p = 38.6 J

body  3

             U_pUp = 0.70 9.8 (2.7-0)

             U_p = 18.5 J

In conclusion, using the definition of gravitational potential energy, we can find the answers for the energy of each object on the highest rung of the ladder are;

     a) expression for gravitational potential energy is  U_p = m g \ \Delta y

     b) Energy value

        * Body 1    U_p = 82.0 J

        * Body 2   U_p = 38.6 J

        * Body  3   U_p = 18.5 J

Learn more here: brainly.com/question/3884855

8 0
3 years ago
8) 8 resistor is connected in **parallel** with a 6 resistor. This
lyudmila [28]

Answer:

The equivalent resistance of the combination is 3.42 ohms.  

Explanation:

We have,

8 ohms resistor is connected in parallel with a 6 ohms resistor. It is required to find the equivalent resistance of this combination.

For a parallel combination, the equivalent resistance is given by :

\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}

Plugging the values of R₁ and R₂, we get :

\dfrac{1}{R_{eq}}=\dfrac{1}{8}+\dfrac{1}{6}\\\\R_{eq}=3.42\ \Omega

So, the equivalent resistance of the combination is 3.42 ohms.

4 0
3 years ago
1. There is a famous intersection in Kuala Lumpur, Malaysia, where thousands of vehicles pass each hour. A 750 kg Tesla Model S
tigry1 [53]

Solution :

Let the positive x-axis is along the East and the positive y direction is along the north.

Given :

Mass of the Tesla car, m_1 = 750 \ kg

Mass of the Ford car, m_2 = 1250 \ kg

Now let the initial velocity of Tesla car in the south direction be = -v_1j

The initial momentum of Tesla car, p_1 = -750 \ v_1

Let the initial velocity of Ford car in the east direction be = v_2 \ i

So the initial momentum of the Ford car is p_2=1250\ v_2 \ i

Therefore, the initial velocity of both the cars is p_i = p_1+p_2

                                                                  =1250 \ v_2 \ i - 750\ v_1 \ j

Now the final velocity of both the cars is v = 18 \ m/s

So the vector form is :

v = 18\cos 32\ i-18 \sin 32 \ j

  = 15.26 \ i - 9.54 \ j

Therefore the momentum after the accident is

p_f=(m_1+m_2) \times v

    =(750+1250) \times (15.26 \ i - 9.54 \ j)

    = 30520\ i -19080\ j

According to the law of conservation of momentum, we know

p_i = p_f

1250 \ v_2 \ i - 750\ v_1 \ j  = 30520\ i -19080\ j

1250 \ v_2 = 30520

v_2=24.4 \ m/s

From, 750\ v_1 = 19080

We get, v_1=25.4 \ m/s

Therefore the speed of Tesla car before collision = 25.4 m/s

The speed of ford car before collision = 24.4 m/s

6 0
3 years ago
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