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erik [133]
3 years ago
9

a museum opened at 8.00 a.m. In the first hour, 350 people purchaced admission tickets. In the second hour, 20% more people purc

hased admission tickets than the first hour. Each admission cost $17.50.
Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0
1st hour 350 purched tickets @ $17.50 each = $6,125

the second hour 20% more people purchased tickets than the first hour - 350 x 20%=70 more than 1st hour.so 70 x $17.50=$1,225 so total sales is $6,125 + 1,225=$7350
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Is this corrrecct??? answe quick!?​
jok3333 [9.3K]

Answer: x = 27

Step-by-step explanation:

2x+3x+45=180º because all of the angles of a triangle add up to 180

5x=180-45

5x=135

x=135/5

x=27

5 0
3 years ago
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Sliva [168]

Answer:

         

Step-by-step explanation:

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Please help me answer number 4! And if you can, please explain!
Leno4ka [110]
If Nathan does 9 minutes of push ups for 3 days, that's 9 divided by 3, which is 3. (9/3=3)  So nathan does 3 minutes of push ups each day, so just multiply each day by 3 to find the correlation between the two.

The Table should look like this: 

# of days      # of Minutes
1                     3
2                     6
3                     9
4                     12
5                     15
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7                     21

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3 years ago
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Vitek1552 [10]
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3 0
3 years ago
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A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow
Mrrafil [7]

Answer:

\displaystyle \frac{54}{5405}.

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

\displaystyle \left(50\atop 5\right) = 2,118,760.

How many out of that 2,118,760 combinations will satisfy the request?

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\displaystyle \left( 28\atop 2\right) = 378.

Number of ways to choose 3 green candies out of a batch of 8:

\displaystyle \left(8\atop 3\right)=56.

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168.

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}.

3 0
3 years ago
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