Question

Write an inequality for X that would give this rectangle an area of at least 117ft^2

Answer 1

Answer:

$117\geq x^2 + 5x$

Step-by-step explanation:

The perimeter of a rectangle is equal to A = l*w where l=length and w=width. Here the length is 5 feet longer than the width or 5+x. This means the width is x. Substitute A=117, l=5+x and x into the formula. But since it must be at least, you will use an inequality sign ≥ for greater than or equal to.

$A \geq l*w\\\\117\geq (x+5)(x)\\\\117\geq x^2 + 5x$