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adoni [48]
3 years ago
9

Write an inequality for X that would give this rectangle an area of at least 117ft^2

Mathematics
1 answer:
irakobra [83]3 years ago
7 0

Answer:

117\geq x^2 + 5x

Step-by-step explanation:

The perimeter of a rectangle is equal to A = l*w where l=length and w=width. Here the length is 5 feet longer than the width or 5+x. This means the width is x. Substitute A=117, l=5+x and x into the formula. But since it must be at least, you will use an inequality sign ≥ for greater than or equal to.

A \geq  l*w\\\\117\geq (x+5)(x)\\\\117\geq x^2 + 5x

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Since, Jesse is building a spice rack.

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From the tables, and definitions of functions, it is found that the function (f - g)(x) is positive in the interval (–∞, –2).

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A similar problem is given at brainly.com/question/24388889

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