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3 years ago

Where can you hear MUSIC on an ocean liner?

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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Y=x-3 determine the slope

Anettt [7]

It is the answer M: 1

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3 years ago

In the diagram below, lines h and s are parallel. If the m∠2 = 70°, what is the angle measurement of m∠1?

crimeas [40]

Geometry

The answer is D because the two sides add up to 180.

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3 years ago

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The selling price of a box of crackers is $1.75 You mark the crackers up to $2.54 . What is the markup percentage?

Aleks04 [339]

The markup percentage is 45.14%

Step-by-step explanation:

The given is:

The selling price of a box of crackers is $1.75
You mark the crackers up to $2.54

We need to find the markup percentage

The markup percentage = $\frac{New-Old}{old}$ × 100%

∵ The selling price of a box of crackers is $1.75

∴ Old = 1.75

∵ You mark the crackers up to $2.54

∴ New = 2.54

- Substitute these values in the rule above

∵ The markup percentage = $\frac{2.54-1.75}{1.75}$ × 100%

∴ The markup percentage = $\frac{0.79}{1.75}$ × 100%

∴ The markup percentage = 0.4514 × 100%

∴ The markup percentage = 45.14%

The markup percentage is 45.14%

Learn more:

You can learn more about percentage in brainly.com/question/1834017

#LearnwithBrainly

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3 years ago

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Write a system of linear inequalities that is given by the following graph. (5 points)

Cerrena [4.2K]

Answer: Hi! I want to know this!

8 0

2 years ago

hus, D satisfying (ABC)DequalsI exists. Why does the expression for D found above also satisfy D(ABC)equalsI, thereby showing

Assoli18 [71]

Complete Question

The complete question is shown on the first uploaded image

Answer:

First Question

Option A is correct

Second Question

Option C is correct

Third Question

$D = A^{-1} * B^{-1} * C^{-1}$

Fourth Question

So substituting for D in (ABC) D = I

$(ABC) * A^{-1} * B^{-1} * C^{-1} = I$

$I = I$

This proof that ABC is invertible

Step-by-step explanation:

From the question we are told that

A , B and C are invertible which means that $A^{-1} , B^{-1}, C^{-1}$ exist

Now

From the question

(ABC) D = I

Where I is an identity matrix

Now when we multiply both sides by $A^{-1}$ we have

$A^{-1} A BCD = A^{-1} * I$

$IBCD = A^{-1}$

Now when we multiply both sides by $B^{-1}$ we have

$B^{-1 } *I BCD = A^{-1} * B^{-1}$

$I CD = A^{-1} * B^{-1}$

Now when we multiply both sides by $C^{-1}$ we have

$C^{-1} * I CD = A^{-1} * B^{-1} * C^{-1}$

$I D = A^{-1} * B^{-1} * C^{-1}$

$D = A^{-1} * B^{-1} * C^{-1}$

So substituting for D in the above equation

$(ABC) * A^{-1} * B^{-1} * C^{-1} = I$

$I = I$

This proof that ABC is invertible

4 0

2 years ago