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3 years ago

Where can you hear MUSIC on an ocean liner?

Mathematics

1 answer:

Dennis_Churaev [7]3 years ago

5 0

Answer:

Step-by-step explanation:

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amy is building a house. the basement floor is at -15 feet. the roof of the house is above the ground 25 feet. express the compa

Deffense [45]

Answer: 375 sq.ft

Step-by-step explanation:

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2 years ago

Read 2 more answers

What is 11% of 96 students

zaharov [31]

Answer:

8.7

Step-by-step explanation:

8.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.78.7

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2 years ago

Consider the following functions

TiliK225 [7]

Step-by-step explanation:

g(5)=3(5)-11

=15-11

f(g(5))=2(4)²+4(4)+10

=2(16)+16+10

=32+26

=58

5 0

3 years ago

An art teacher is pouring paint into containers that each hold 1/2, gallon. How many

irina1246 [14]

Answer:

10 gallons

Step-by-step explanation:

Multiply 20 by 1/2.

20 x 1/2 = 10

Hope it helps!

Let me know if it doesn't, I can make it right.

5 0

2 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago