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maw [93]
3 years ago
12

Where can you hear MUSIC on an ocean liner?

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
5 0

Answer:

Step-by-step explanation:

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Which graph best represents the relationship between time and the number of teams registered?
alexdok [17]
<h2>Explanation:</h2><h2></h2>

The complete question is in the attached file. So we have to choose between two graphs. On of them is a linear model while the other is an exponential model. From the statements, we have a relationship between time and the number of teams registered. So we can establishes variables in the following form:

x:\text{Time} \\ \\ y:\text{Number of teams registered}

We also know that each week 6 teams register to participate, so:

\bullet \ \text{For week 0:} \rightarrow \text{0 teams registered} \\ \\ \bullet \ \text{For week 1:} \rightarrow \text{6 teams registered} \\ \\ \bullet \ \text{For week 2:} \rightarrow \text{12 teams registered (Because 6+12)} \\ \\ \bullet \ \text{For week 3:} \rightarrow \text{18 teams registered (Because 12+6)}

As you can see, as x increases one week, y increases at a constant ratio of 6. Therefore, this can be modeled by a linear function given by the form:

y=6x

In conclusion, <em>the linear model (first graph below) is the one that bests represents  the relationship between time and the number of teams registered.</em>

7 0
3 years ago
Here is a list of numbers:<br> 7.3, 4.2, 7.3, 6.7, 4.2, 9.3, 1.2 ,1.1 ,6.4 ,8<br> State the median.
morpeh [17]
First order the numbers then cross out the numbers till in the middle the numbers 6.4 and 6.7 add then divide by two to get the middle and the median
13.1/2 =6.55

Answer:6.55

1.1
1.2
4.2
4.2
6.4
6.7
7.3
7.3
8
9.3
6 0
3 years ago
What is the area of this parallelogram PLEASE HELP QUICKLY!!!20 points!!!
olga nikolaevna [1]

Answer:

72

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa
barxatty [35]

z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}

We're given that f_x(6,1)=3 and f_y(6,1)=-1, and want to find \frac{\partial z}{\partial v}(1,2).

By the chain rule, we have

\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}

and

\dfrac{\partial x}{\partial v}=2v

\dfrac{\partial y}{\partial v}=-1

Then

\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)

(because the point (x,y)=(6,1) corresponds to (u,v)=(1,2))

\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}

4 0
3 years ago
How do I solve ?? It’s cylinders
UkoKoshka [18]
V= 3.14r^2h
10/2= r
5^2= 25
(3.14)(25)(6)
V=471
3 0
4 years ago
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