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Rufina [12.5K]
4 years ago
6

How many times does the kinetic energy of a car increase when traveling 60mph as opposed to traveling 30mph?

Physics
1 answer:
g100num [7]4 years ago
6 0
The kinetic energy increases 4 times
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Jasmine is a cook, and she wants to buy new equipment. She is presented with dishes made of copper, clay, plastic, and glass. Sh
-Dominant- [34]
I would say that the answer is 4.) because if she does most of cooking on the stove, that would allow us to make the assumption that she is using heat and therefore requires and apparatus that conducts heat. Copper is also a metallic that is known to be conductive.
5 0
4 years ago
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Block M = 7.50 kg is initially moving up the incline and is increasing speed with a = [09]____________________ m/s2 . The applie
Aliun [14]

Answer:

a) 73.2N

b) 66.6N

c) 20.28N

Explanation:

F= mg=7.5×9.8=73.5N

Force parallel to the plane Fp= 73.5sin25= 31.06N

b) Fv= 73.5 cos25= 66.6N

c) Ff= u×Fv= 0.312×66.6=20.28N

a) Normal ForceFn= F/(cos25) - Fp - Ff = ma

1.1F -31.06-20.28=7.5×3.82

1.1F -51.84=28.65

1.1F= 28.65+51.84

F= 80.49/1.1

F= 73.2N

4 0
3 years ago
Two different charges, q1 and q2, are placed at two different locations, one charge at each location. The locations have the sam
Mars2501 [29]

Answer:

No

Explanation:

Electric potential is the work done to bring a unit of charge (1 C) from infinity to a point inside an electric field.

Electric potential energy of a charge q is the energy required to keep it in an electric potential V. Electric potential energy is given by,

U = qV

Hence even if the two charges are on an equipotential surface (surface where the potential is the same at all points), the potenial energy will be different if the magnitude or nature of the charges are different.

5 0
3 years ago
A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction
hoa [83]

Given:

Applied stress, \sigma = 0.45 MPa

Critical Resolved Stress,  T_{cRss}= 0.242 MPa

Solution:

a). According to the question, orientation of tensile load is along [1 1 1],

\sigma = 0.45 MPa

Now, for resolved shear stress,  \t_{Rss} along [1 0 1] within (1 1 T)

let  '\theta' be the angle between [1 1 1] and [1 0 1], then by coordinate formula:

cos\theta = \frac{1\times 1 + 1\times 0 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+0^{2}+1^{2}}}}

cos\theta = \sqrt{\frac{2}{3}}

let  '\phi' be the angle between [1 1 1] and [1  1 1], then by coordinate formula:

cos\phi  = \frac{1\times 1 + 1\times 1 + 1\times 1}{\sqrt{1^{2}+1^{2}+1^{2}\sqrt{1^{2}+1^{2}+1^{2}}}}

cos\phi = 1

Now, for the resolved components along [1 0 1]

\t_{Rss}  = \sigma  cos\theta cos\phi

\t_{Rss} = 0.45\times 10^{6}\times \sqrt{\frac{2}{3}}\times 1 = 0.3673 MPa

b).  For required tensile stress to produce  T_{cRss}= 0.242 MPa:

\sigma _{1} = \frac{T_{cRss}}{cos\theta  cos\phi }

\sigma _{1} = \frac{0.242\times 10^{6}}{\sqrt{\frac{2}{3}}\times 1}

\sigma _{1} = 0.2964 MPa

5 0
3 years ago
Which of the following statements are evidence that gases do not always behave ideally? Check all that apply.?
yaroslaw [1]

Your answer will be A

Hope this helps you out a little


8 0
3 years ago
Read 2 more answers
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