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asambeis [7]
4 years ago
12

What is the main similarity between ""fog"" and frost’s poem mending wall?

Physics
2 answers:
Anettt [7]4 years ago
7 0

Answer:

They both use iambic pentameter

Explanation:

<em>The main similarity between "fog" and frost's poem "mending wall" is that they both use iambic pentameter </em>

<em> Iambic pentameter is a line of verse with five metrical feet, each comprising of one short or unstressed syllable which is followed by one long or stressed) syllable, Currently, this technique is certainly the usual technique that is used in a poetry.</em>

muminat4 years ago
5 0

Answer:

Both use everyday language.

Explanation:

Language is the system through which man or animals communicate their ideas and feelings, either through speech, writing or other conventional signs, being able to use all the senses to communicate.

The term language is of Latin lingua origin.   The human being uses a complex language that expresses with sound sequences and graphic signs. Animals, meanwhile, communicate through sound and body signs, which even man has not been able to decipher, and which in many cases are far from simple.

Depending on the social context in which the language is produced, the speaker can use the formal language or technical language that is produced in situations that require the use of the standard language, for example, in classrooms or work meetings or language informal or everyday language that is used when there is intimacy between speakers, using colloquial expressions.

Everyday language is the use of informal, familiar language and is characterized by being a spontaneous, relaxed and expressive language. In everyday language, the speaker uses onomatopoeia, short sentences, repetitions, redundancies, among others. In turn, technical language is used by scientific and professional people.

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Energy that flows from an objective with a higher temperature to an object with a lower temperature
dalvyx [7]
That's THERMAL energy, often referred to as "heat".
7 0
3 years ago
un motor electric efectueaza un lucru mecanic de 864 j in 0.5 min.tensiunea la bornele sale este de 12v si este parcurs de un cu
GrogVix [38]

Answer:

96%

Explanation:

To find the values of the motor efficiency you use the following formula:

E=\frac{P_o}{P_i}100

P_o: output power = 864J/0.5min=864J/30s=28.8W

P_i: input power = I*V = (3A)(12V) = 36W

By replacing this values you obtain:

E=\frac{28.8W}{30W}*100=96\%

hence, the motor efficiency is about 96%

traslation:

Pentru a găsi valorile eficienței motorului, utilizați următoarea formulă:

P_o: putere de ieșire = 864J / 0.5min = 864J / 30s = 28.8W

P_i: putere de intrare = I * V = (3A) (12V) = 36W

Înlocuind aceste valori obțineți:

prin urmare, eficiența motorului este de aproximativ 96%

3 0
3 years ago
A 23.0 kg iron weightlifting plate has a volume of 2920 cm3 . what is the density of the iron plate in g/cm3?
yanalaym [24]
The first thing you should know for this case is that density is defined as the quotient between mass and volume:
 D = M / V
 In addition, you should keep in mind the following conversion:
 1Kg = 1000g
 Substituting the values we have:
 D = (23.0 * 1000) / (2920) = 7.88 g / cm ^ 3
 answer
 the density of the iron plate is 7.88 g / cm ^ 3
8 0
3 years ago
what occurs in a chemical reaction? A. Reactants are formed without chemical bonds being broken B. Reactants are formed from pro
Ann [662]
The answer is D. Products are formed from reactants by the breaking and forming of new bonds. 
3 0
3 years ago
Read 2 more answers
Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.6×104 m/s when at a distance
xz_007 [3.2K]

Answer:

v₂ = 7.6 x 10⁴ m/s

Explanation:

given,

speed of comet(v₁) = 1.6 x 10⁴ m/s

distance (d₁)= 2.7 x 10¹¹ m

to find the speed when he is at distance of(d₂) 4.8 × 10¹⁰ m

v₂ = ?

speed of planet can be determine using conservation of energy

K.E₁ + P.E₁ = K.E₂ + P.E₂

\dfrac{1}{2}mv_1^2-\dfrac{GMm}{r_1} = \dfrac{1}{2}mv_2^2-\dfrac{GMm}{r_2}

\dfrac{1}{2}v_1^2-\dfrac{GM}{r_1} = \dfrac{1}{2}v_2^2-\dfrac{GM}{r_2}

v_2^2= v_1^2 + \dfrac{2GM}{r_2}-\dfrac{2GM}{r_1}

v_2= \sqrt{v_1^2 +2GM(\dfrac{1}{r_2}-\dfrac{1}{r_1})}

v_2= \sqrt{(1.6\times 10^4)^2 +2\times 6.67 \times 10^{-11}\times 1.99 \times 10^{30}(\dfrac{1}{4.8\times 10^{10}}-\dfrac{1}{2.7\times 10^{11}})}

v₂ = 7.6 x 10⁴ m/s

3 0
3 years ago
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