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Vladimir [108]
3 years ago
13

Compare the energy consumption of two commonly used items in the household. Calculate the energy used by a 1.20 kW toaster oven,

W toaster , which is used for 6.00 minutes , and then calculate the amount of energy that an 11.0 W compact fluorescent light (CFL) bulb, W light , uses when left on for 11.00 hours .
Physics
1 answer:
9966 [12]3 years ago
5 0

Answer:

The energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

Explanation:

Power of toaster oven, P = 1.2 kW

Time, t = 6 minutes = 360 s

The energy used by toaster oven is given by :

E=P\times t\\\\E=1.2\times 10^3\times 360\\\\E=432000\ J\\\\E=432\ kJ

Power of fluorescent light (CFL) bulb, P' = 11 W

Time, t' = 11 h = 39600 s

Energy used by fluorescent light (CFL) bulb is given by :

E'=P'\times t'\\\\E'=11\times 39600\\\\E'=435600\ J\\\\E'=435\ kJ

So, the energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

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Free_Kalibri [48]
The total distance covered by the person is 12 times the height of each stair:
\Delta h=12 \cdot 30 cm=360 cm=3.60 m

The work done by the person to climb the stairs is equal to the increase in his gravitational potential energy:
W= \Delta U=mg \Delta h=(45 kg)(9.81 m/s^2)(3.60 m)=1589.2 J

And therefore, the power generated by the person in 12 s is the work done divided by the time taken:
P= \frac{W}{t}= \frac{1589.2 J}{12 s}=132.3 W

So, the correct answer is B.
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4 years ago
Pete is driving down a highway and sees a brown sign. All of the brown signs
pychu [463]

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C

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3 years ago
A light beam in glass (n = 1.5) reaches an air-glass interface, at an angle of 60 degrees from the surface. What is the angle of
tester [92]

Answer:

θ₂ = 35.26°

Explanation:

given,

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refractive index of glass, n₂ = 1.5

angle of incidence, θ₁ = 60°

angle of refracted light, θ₂ = ?

using Snell's Law

n₁ sin θ₁ = n₂ sin θ₂

1 x sin 60° = 1.5 sin θ₂

sin θ₂ = 0.577

θ₂ = sin⁻¹(0.577)

θ₂ = 35.26°

Hence, the refracted light is equal to  θ₂ = 35.26°

7 0
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Answer:

(a) Negative

(b) Positive

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Here is a question on sign.

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(b) When the rock is coming down, it is actually working with gravity. So in this case, the sign will ne positive

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Answer:

Explanation:

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Now the area is halved and the separation is tripled.

The new capacitance is

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Initial potential energy is given by

U=\frac{q^{2}}{2C}

here the charge is constant

The new energy is given by

U'=\frac{6q^{2}}{2C}

U' = 6 U

The energy becomes six times the initial value.

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