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Vladimir [108]
3 years ago
13

Compare the energy consumption of two commonly used items in the household. Calculate the energy used by a 1.20 kW toaster oven,

W toaster , which is used for 6.00 minutes , and then calculate the amount of energy that an 11.0 W compact fluorescent light (CFL) bulb, W light , uses when left on for 11.00 hours .
Physics
1 answer:
9966 [12]3 years ago
5 0

Answer:

The energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

Explanation:

Power of toaster oven, P = 1.2 kW

Time, t = 6 minutes = 360 s

The energy used by toaster oven is given by :

E=P\times t\\\\E=1.2\times 10^3\times 360\\\\E=432000\ J\\\\E=432\ kJ

Power of fluorescent light (CFL) bulb, P' = 11 W

Time, t' = 11 h = 39600 s

Energy used by fluorescent light (CFL) bulb is given by :

E'=P'\times t'\\\\E'=11\times 39600\\\\E'=435600\ J\\\\E'=435\ kJ

So, the energy consumption by toaster oven is 432 kJ and that of fluorescent light (CFL) bulb is 435 kJ.

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Calculate the mass (in g) of 346 cm³ of polythene. The density of polythene is 0.95 g/cm³. Give your answer to 2 decimal places.
IceJOKER [234]

Answer:

M = 328.70g

Explanation:

From the given values:

V = 346 cm³

M of 1 cm³ of Polythene = 0.95g or 95/100g

Solve:

M = <u>(95×346)</u>

10

= <u>3</u><u>2</u><u>8</u><u>7</u><u>0</u>

100

M = 328.70g

8 0
2 years ago
Calculate the tangential speed of a yo-yo twirled at the end of a 4 meter long string at 2 revolutions per second.
Oliga [24]

Answer: 50 m/s

Explanation: speed v = 2· pi·n·r = 2· 3.14· 2 s^-1· 4 m

8 0
2 years ago
Whats it called when a force can change the shape of an object?
alekssr [168]

Force applied causes deformation in the object. It changes the relative positions of constituent particles in the crystal lattice.
As soon as that happens, the interatomic or intermolecular forces come into play and they, tend to restore the solid back to it's original shape.

This restoring force per unit area is called Stress . When external forces are removed, the internal forces tend to restore the solid back.
This property is called Elasticity .

However, no material is perfectly elastic and what happens is that, the body is not able to restore itself completely.

 
3 0
3 years ago
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SOH-CAH-TOA is used to solve for the ________
Misha Larkins [42]

Answer:

c. initial (x and y)

Explanation:

When a projectile is launched at a velocity with a launch angle, to solve it, we must first resolve the initial velocity into the x and y components. To do this will mean we have to treat it like a triangle due to the launch angle and the direction of the projectile.

Therefore, we will have to make use of trigonometric ratios which is also known by the mnemonic "SOH CAH TOA"

Thus, this method resolves the initial x and y velocities.

3 0
3 years ago
While entering a freeway, a car accelerates from rest at a rate of 2.40 m/s2 for 12.0 s. (a) Draw a sketch of the situation. (b)
ArbitrLikvidat [17]

Answer:

a) See attached picture, b) We know the initial velocity = 0, initial position=0, time=12.0s, acceleration=2.40m/s^{2}, c) the car travels 172.8m in those 12 seconds, d) The car's final velocity is 28.8m/s

Explanation:

a) In order to draw a sketch of the situation, I must include the data I know, the data I would like to know and a drawing of the car including the direction of the movement and its acceleration, just like in the attached picture.

b) From the information given by the problem I know:

initial velocity =0

acceleration = 2.40m/s^{2}

time = 12.0 s

initial position = 0

c)

unknown:

displacement.

in order to choose the appropriate equation, I must take the knowns and the unknown and look for a formula I can use to solve for the unknown. I know the initial velocity, initial position, time, acceleration and I want to find out the displacement. The formula that contains all this data is the following:

x=x_{0}+V_{x0}t+\frac{1}{2}a_{x}t^{2}

Once I got the equation I need to find the displacement, I can plug the known values in, like this:

x=0+0(12s)+\frac{1}{2}(2.40\frac{m}{s^{2}} )(12s)^{2}

after cancelling the pertinent units, I get that  my answer will be given in meters. So I get:

x=\frac{1}{2} (2.40\frac{m}{s^{2}} )(12s)^{2}

which solves to:

x=172.8m

So the displacement of the car in 12 seconds is 172.8m, which makes sense taking into account that it will be accelerating for 12 seconds and each second its velocity will increase by 2.4m/s.

d) So, like the previous part of the problem, I know the initial position of the car, the time it travels, the initial velocity and its acceleration. Now I also know what its final position is, so we have more than enough information to find this answer out.

I need to find the final velocity, so I need to use an equation that will use some or all of the known data and the unknown. In order to solve this problem, I can use the following equation:

a=\frac{V_{f}-V_{0} }{t}

Next, since I need to find the final velocity, I can solve the equation just for that, I can start by multiplying both sides by t so I get:

at=V_{f}-V_{0}

and finally I can add V_{0} to both sides so I get:

V_{f}=at+V_{0}

and now I can proceed and substitute the known values:

V_{f}=at+V_{0}

V_{f}=(2.40\frac{m}{s^{2}}} (12s)+0

which solves to:

V_{f}=28.8m/s

8 0
3 years ago
Read 2 more answers
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