Answer:
0.36
Explanation:
The maximum force of friction exerted by the surface is given by:
(1)
where
is the coefficient of friction
N is the normal reaction
The shed's weight is 2200 N. Since there is no motion along the vertical direction, the normal reaction is equal and opposite to the weight, so
N = 2200 N
The horizontal force that is pushing the shed is
F = 800 N
In order for it to keep moving, the force of friction (which acts horizontally in the opposite direction) must be not greater than this value. So the maximum force of friction must be
And substituting the values into eq.(1), we can find the maximum value of the coefficient of friction:
Answer:
tortoise distance w.r.t sloth is 28.08 m further
Explanation:
given data
average speed v1 = 0.037 m/s
walking speed v2 = 0.076 m/s
time t = 12 min = 720 seconds
to find out
how much tortoise have gone wrt sloth
solution
we find here first tortoise walk that is
distance d1 = v2 × t
distance d1 = 0.076 × 720
distance d1 = 54.72 m
and sloth walk distance
distance d2 = v1 × t
distance d2 = 0.037 × 720
distance d2 = 26.64 m
and so
tortoise distance w.r.t sloth = d1 - d2
tortoise distance w.r.t sloth = 54.72 - 26.64 = 28.08
tortoise distance w.r.t sloth is 28.08 m further
The lowest rock layer is a layer that must be rich in organic matter that was subjected to heat and pressure over time during the formation of oil and gas.
<h3>What is the lowest rock layer?</h3>
The lowest rock layer refers to the lowermost part of the Earth's mantle, which is a thin rock layer (approximately 250 km).
In the Earth, the layers of rocks are progressively deposited, thereby pressing them to the bottom to generate sedimentary rocks.
The lowest rock layers on the bottom must be rich in organic matter to form fossil fuels.
Learn more about rock layers here:
brainly.com/question/25846908
Answer:
x₁ = 0.1878 m
Explanation:
For this exercise we will use conservation of energy
starting point. Highest point
Em₀ = U = m g h
final point. Lowest point with fully compressed spring
Em_f = K_e + U
Em_f = ½ K x² + m g x
energy is conserved
Em₀ = Em_f
m g h = ½ K x² + m g x
½ K x² + mg (x- h) = 0
let's substitute
½ 7.3 x² + 0.030 9.8 (x- 0.25) = 0
3.65 x² + 0.294 (x- 0.25) = 0
x² + 0.080548 (x- 0.25) = 0
x² - 0.020137 + 0.080548 x = 0
x² + 0.080548 x - 0.020137 = 0
let's solve the quadratic equation
x = [0.080548 ±√ (0.080548² + 4 0.020137)] / 2
x = [0.080548 ± 0.29502] / 2
x₁ = 0.1878 m
x₂ = -0.1072 m
These are the compression and extension displacement of the spring
