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dimaraw [331]
3 years ago
7

A grating that has 3900 slits per cm produces a third-order fringe at a 27.0° angle. What wavelength of light is being used?

Physics
1 answer:
Dmitry [639]3 years ago
7 0

Answer:

Wavelength of light used is 387 nm.

Explanation:

It is given that,

Number of lines, N = 3900 slits per cm

Number of lines per m, N=390000\ lines/m

Third order fringe is formed at angle of, \theta=27^{\circ}

We need to find the wavelength of light being used. The equation of grating is given by :

d\ sin\theta=n\lambda, n = 3

And, d=\dfrac{1}{N}=\dfrac{1}{390000}

d=2.56\times 10^{-6}\ m

\lambda=\dfrac{d\ sin\theta}{n}

\lambda=\dfrac{2.56\times 10^{-6}\times \ sin(27)}{3}

\lambda=3.87\times 10^{-7}\ m

\lambda=387\ nm

So, the wavelength of light used is 387 nm. Hence, this is the required solution.

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Margaret [11]

Answer:

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Explanation:

Given the data in the question;

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ω = 1 / √( ( 20 × 10⁻³ H ) × ( 8.0 × 10⁻¹² F) )

ω = 1 / √( 1.6 × 10⁻¹³  )

ω = 1 / 0.0000004

ω = 2.5 × 10⁶ s⁻¹

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V_m =  V₀sin( ωt )

we substitute

25V =  25V × sin( 2.5 × 10⁶ s⁻¹ × t )

25V =  25V × sin( 2.5 × 10⁶ s⁻¹ × t )

divide both sides by 25 V

sin( 2.5 × 10⁶ × t ) = 1

( 2.5 × 10⁶ × t ) = π/2

t = 1.570796 / (2.5 × 10⁶)

t = 0.6283 × 10⁻⁶ s

t = 0.6283 μs

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b) What is the inductor current at that time?

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{ sin(ωt) = 1 )

I(t) = V₀√(C/L)

we substitute

I(t) = 25V × √( ( 8.0 × 10⁻¹² F ) / ( 20 × 10⁻³ H ) )

I(t) = 25 × 0.00002

I(t) = 0.0005 A

I(t) = 0.5 mA

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