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tatyana61 [14]
3 years ago
5

A scientist is measuring the temperature change in a chemical compound. The temperature dropped 11 degrees F per hour from the o

riginal temperature. After 4 hours, the temperature was 90 degrees F. Find the compounds original temperature

Mathematics
1 answer:
devlian [24]3 years ago
6 0
The original temperature was 134

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The point B lies on the segment AC.
svet-max [94.6K]

Answer:

(9, -5)

Step-by-step explanation:

The vector AC has coordinates (27, -18), because:

21 - (-6) = 27

-13 - 5 = -18

If the ratio of AB to BC is 5 to 4, it means that

AB = [5/(5+4)]AC = (5/9)AC

Therefore, we have

AB = (5/9)AC = (5/9) (27, -18) = (15, -10)

Which means that:

xB - xA = 15 <=> xB - (-6) = 15 <=> xB + 6 = 15 <=> xB = 9

yB - yA = -10 <=> yB - 5 = -10 <=> yB = -10 + 5 <=> yB = -5

So B has coordinates (9, -5).

4 0
2 years ago
Which of the following is needed to solve the area of a square
blagie [28]

Answer:

C

Step-by-step explanation:

This is because

Area= L×L

therefore the length is needed

5 0
3 years ago
Identify the lengths of QS and SR
Semenov [28]
<span>The bisector of an angle of a triangle divides the opposite side into segments that are proportional to the adjacent sides  </span>⇒
<span>
10/12 = (3x+2)/(5x-0.4)
10(5x-0.4) = 12(3x+2)
50x - 4 = 36x + 24
50x - 36x = 24 + 4
14x = 28
x = 28/14
x = 2

QS = 3x + 2 = 3*2 + 2 = 6 + 2 = 8 
SR = 5x - 0.4 = 5*2 - 0.4 = 10 - 0.4 = 9.6

Answer is QS=8, SR=9.6
</span><span>
</span>
3 0
3 years ago
Find the equation of the tangent line to the curve y equals left parenthesis x minus 3 right parenthesis superscript 7 baseline
Rashid [163]

We have been given the expression to be y=(x-3)^7(x+1)^2

Since we need to find the tangent at a point, we will have to find the derivative of y as the slope of the tangent at a given point on the curve is always equal to value of the derivative at that point.

Thus, we have to find \frac{dy}{dx}=\frac{d}{dx} (x-3)^7(x+1)^2

We will use the product rule of derivatives to find \frac{dy}{dx}

Thus, y'=7(x-3)^6(x+1)^2+(x-3)^7\times2(x+1) (using the product rule which states that (fg)'=f'g+fg')

Taking the common factors out we get:

y'=(x-3)^6(x+1)(7(x+1)+2(x-3))

y'=(x-3)^6(x+1)(7x+7+2x-6)=(x-3)^6(x+1)(9x+1)

Thus, y' at x=4 is given by:

y'_{x=4}=Slope of the tangent of y at x=4=m

Thus, m=(4-3)^6(4+1)(9\times4+1)=185

Now, the equation of the tangent line which passes through (x_{1}, y_{1}) and has slope m is given by:

y-y_{1}=m(x-x_{1})

Thus, the equation of the tangent line which passes through (4,25) and has the slope 185 isy-25=185(x-4)

Which can be simplified to y=185x-740+25=185x-715

Thus, y=185x-715

This is the required equation of the tangent.

3 0
3 years ago
Which association best describes the scatter plot?
Pepsi [2]
It depends completely on the specific scatter plot. Do you have an image? If the scattering is moving upwards as you go right on the x-axis it is a positive correlation.

3 0
3 years ago
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