If an isotope of uranium, uranium-235, has 92 protons, how many protons does the isotope uranium-28 have?
1 answer:
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Answer:
0.4912 kJ/K
Explanation:
Using steam table, the properties of water at stage 1 can be determined:
= 400 kPa
= 60°C
Therefore, from steam table:
specific volume
entropy
Calculating the specific volume of water after the partition is removed, since the mass is constant and volume of water is doubled:
Final pressure of water in the tank =
dryness factor after removing the partition
Therefore:
Thus, the entropy change is:
Δs =
Therefore, the entropy change of water is 0.4912 kJ/K
The question is incomplete. Complete question is attached below:
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Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.
...........................................................................................................................
Answer:
Given: conc. of HBr = 1.4 M
Volume of HBr = 15.4 mL
Volume of KOH = 22.10 mL
We know that, M1V1 = M2V2
(HBr) (KOH)
Therefore, M2 = M1V1/V2
= 1.4 X 15.4/22.10
= 0.9756 M
Concentration of KOH is 0.9756 M.