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aleksley [76]
3 years ago
11

What is the density of chlorine gas (MM = 71.0glmol) at 1.50 atm and 25.0C

Chemistry
1 answer:
IrinaVladis [17]3 years ago
5 0

Answer: D=4.35g/L

Explanation:

The formula for density is D=\frac{M}{V}. M is mass in grams and V is volume in liters.

Since we are give pressure and temperature, we can use the ideal gas law to find moles/volume. FInding moles/volume would give us the base for density. All we would have to do is convert moles to grams.

Ideal Gas Law: PV=nRT

\frac{n}{V} =\frac{P}{RT}

\frac{n}{V}=\frac{1.50 atm}{(0.08206Latm/Kmol)(25+274.15K)}

\frac{n}{V} =\frac{0.061309mol}{L}

Now that we have moles, we can use molar mass of chlorine gas to find grams.

0.061309mol*\frac{71.0g}{mol} =4.3529g

With our grams, we can find our density.

D=\frac{4.3529g}{L}

We need correct significant figures so our density is:

D=\frac{4.35g}{L}

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The solution is as follows:

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Use the ICE approach

        borneol  →  isoborneol
I         0.0972           0.0486
C         -x                     +x
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Total moles = 0.1458

Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P

0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832 

Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
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3 years ago
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Carbon can react with oxygen to form carbon dioxide. Which of the following statements about this chemical change is true? ... Carbon and oxygen atoms are destroyed as new atoms are formed. Carbon and oxygen atoms have the same properties as molecules of carbon dioxide.

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