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Marta_Voda [28]
3 years ago
14

Suggest a reason why the equilibrium between succinic acid and acetic anhydride lies on the side favoring formation of acetic ac

id and succinic anhydridse
Chemistry
1 answer:
Sergio [31]3 years ago
7 0
Due to <span>succinic anhydride is cyclic 5 membered anhydride which is stable compared to acetic anhydride which is open chain anhydride. hence equilibrium favors one side towards succinic anhydride.
Also: </span><span>Since, acetic acid is stronger acid than succinic acid, it will form its salt rather than succinic acid</span>
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A solution is prepared by dissolving 27.0 g of urea [(NH2)2CO], in 150.0 g of water. Calculate the boiling point of the solution
andrew11 [14]

<u>Answer:</u> The boiling point of solution is 101.56°C

<u>Explanation:</u>

Elevation in boiling point is defined as the difference in the boiling point of solution and boiling point of pure solution.

The equation used to calculate elevation in boiling point follows:

\Delta T_b=\text{Boiling point of solution}-\text{Boiling point of pure solution}

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=iK_bm

Or,

\text{Boiling point of solution}-\text{Boiling point of pure solution}=i\times K_b\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Boiling point of pure water = 100°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 0.52°C/m.g

m_{solute} = Given mass of solute (urea) = 27.0 g

M_{solute} = Molar mass of solute (urea) = 60 g/mol

W_{solvent} = Mass of solvent (water) = 150.0 g

Putting values in above equation, we get:

\text{Boiling point of solution}-100=1\times 0.52^oC/m\times \frac{27\times 1000}{60\times 150}\\\\\text{Boiling point of solution}=101.56^oC

Hence, the boiling point of solution is 101.56°C

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Hope this helps:)

6 0
3 years ago
Read 2 more answers
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