Answer:
The required P value is 0.0901.
The critical value for the test statistic is 1.645.
Step-by-step explanation:
Consider the provided information.
The test statistic of z=1.34 is obtained when testing the claim that p> 0.1
It is given given that z=1.34 as the claim has greater than inequality so it is a right tailed test.
Part (A) P-value
From the Standard normal distribution table 
.
Therefore,
Hence, the required P value is 0.0901.
Part (B) The critical value(s) is/are z=
It is given that the significance level is α=0.05
Using standard z value table we get the critical value for the test statistic is 1.645.
Hence, the critical value for the test statistic is 1.645.
Slope=-5
as the line goes 5 down and 1 right
Answer:
Step-by-step explanation:
The fish population after t years can be modeled by the following equation:
In which F(0) is the initial population and r is the constant rate of decay.
Year one the fish population was 18000
This means that 
In year three the fish population was 8000 fish.
Two years later, so 
So
Length of the rectangular patio = 12 1/2 feet
= 25/2 feet
Area of the rectangular patio = 103 1/8 square feet
= 825/8 square feet
Let us assume the width of the rectangular patio = x feet
Then
Area of the rectangular patio = Length * Width
825/8 = (25/2) * x
25x/2 = 825/8
25x = (825 * 2)/8 feet
25x = 825/4 feet
x = 825/(4 * 25) feet
= 33/4 feet
= 8 1/4 feet
So the width of the rectangular patio is 8 1/4 feet. I hope the procedure is clear enough for you to understand.
